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katrin2010 [14]

3 years ago

15

a metal rod 24mm diameter and 2m long is subjected to an axial pull of 40 kN. If the rod is 0.5mm, then find the stress-induced

and value of the youngs modulus

1 answer:

ozzi3 years ago

8 0

Answer:

i dont know but i will take the points tho hahah

Explanation:

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Be-16 a garbage dumping placard must be prominently posted on boats longer than what size?

Crank

Answer:

26 feet and longer boats that have garbage dumping placard must be prominently posted and the boats which are 40 feet and longer must have the written waste management plan.

4 0

3 years ago

How do you produce a well-constructed survey questionnaire?

Anni [7]

Answer:

Explanation:

Define the purpose of the survey.

Make every question count.

Keep it short and simple.

Ask direct questions.

Ask one question at a time.

Avoid leading and biased questions.

5 0

2 years ago

This question is in C programming.Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the

andriy [413]

Answer:

Replace

/* Your solution goes here */

with the following;

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

newScores[SCORES_SIZE - 1] = oldScores[0];

The full program becomes

#include

int main(void) {

const int SCORES_SIZE = 4;

int lowerScores[SCORES_SIZE];

int i;

for (i = 0; i < SCORES_SIZE; ++i) {

scanf("%d", &(lowerScores[i]));

}

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

newScores[SCORES_SIZE - 1] = oldScores[0];

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", lowerScores[i]);

}

printf("\n");return 0;

}

What the included code segment does it that;

for (i = 0; i < SCORES_SIZE - 1; i++) {

newScores[i] = oldScores[i + 1];

}

The above assigns the values of array oldScores to newScores starting with the second element of array oldScores till the last.

newScores[SCORES_SIZE - 1] = oldScores[0];

The above line then assigns the first element of oldScores to the first element of newScores array

7 0

3 years ago

4 Error-Correcting Polynomials (a) Alice has a length 8 message to Bob. There are 2 communication channels available. When n pac

yKpoI14uk [10]

( $m_{1}$ , $m_{2}$ , $m_{3}$ ) = (3, -6, 3)

<u>Explanation:</u>

Given data,

$p=m_{1} x^{2}+m_{2} x+m_{3}$

5 packets are delivered by channel, which was randomly taken.

0(P(0)), 1(P(1)), 2(P(2)), 3(P(3)), 4(P(4))

Bob receives are

(0,3) (1,0) (2,3) (3,0) (4,3)

P(0) = 3

P(1) = 0

P(2) = 3

P(3) = 0

P(4) = 3

The given equation is

$p=m_{1} x^{2}+m_{2} x+m_{3}$

Solution:

$p(0)=m_{1}(0)+m_{2}(0)+m_{3}$ = 3

$m_{3}$ = 3

$p(1)=m_{1}+m_{2}+m_{3}=0$

$m_{1} + m_{2}$ = - 3

$m_{2} = -3 -m_{1}$

$p(2)=4 m_{1}+2 m_{2}+m_{3}$ = 3

$4 m_{1}+2 m_{2}$ = 0

$2 m_{1}+m_{2}=0$

$P(3)=9 m_{1}+3 m_{2}+m_{3}$ = 0

$3 m_{1}+m_{2}+3=0$

$P(4)=16 m_{1}+4 m_{2}+m_{3}$ = 3

$4 m_{1}+m_{2}$ = 0

From P(1) and P(2)

$m_{2} = -3 -m_{1}$

$2 m_{1}+m_{2}=0$

$2 m_{1}-3-m_{1}=0$

-3 + $m_{1}$ = 0

$m_{1}$ = 3

$m_{2}$ = -6

( $m_{1}$ , $m_{2}$ , $m_{3}$ ) = (3, -6, 3)

7 0

3 years ago

It is required to design and implement: 1. A counter which counts from 0 to 255 with seven segment display.

liubo4ka [24]

Answer:

A counter which counts from 0 to 255 with seven segment display

Timer Mode Control (TMOD)

Explanation:

5 0

3 years ago