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katrin2010 [14]
2 years ago
15

a metal rod 24mm diameter and 2m long is subjected to an axial pull of 40 kN. If the rod is 0.5mm, then find the stress-induced

and value of the youngs modulus
Engineering
1 answer:
ozzi2 years ago
8 0

Answer:

i dont know but i will take the points tho hahah

Explanation:

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Jordan's dad made a new recipe for dinner. Jordan looked at the food and saw that it was white, yellow, and purple in color. She
zhenek [66]

Answer:

Jordan used her eyes to see the food, her touch to feel the food, and her nose to smell the food, and lastly, but most importantly, she used her mouth to taste the food.

7 0
2 years ago
The undisturbed soil at given borrow pit is found to have the following property:
tankabanditka [31]

Answer:

Check the explanation

Explanation:

Determine the weight o ids in the each truck °slim the relation,  

W,=\frac{W}{1+w}

Here, W is net weight of soil and water on the truck and w is water content  

substitute 72 7 kN for W and 15% for w.

you will need to also determine the number of truck loads required using the relation:

Number of truck loads required = \frac{W_{sc} }{W_{s}}

Kindly check the attached image below for the full explanation to the question above.

7 0
3 years ago
The compressed-air tank has an inner radius r and uniform wall thickness t. The gage pressure inside the tank is p and the centr
Sedaia [141]

Answer:

Explanation:

Given that:

The Inside pressure (p) = 1402 kPa

= 1.402 × 10³ Pa

Force (F) = 13 kN

= 13 × 10³ N

Thickness (t) = 18 mm

= 18 × 10⁻³ m

Radius (r) = 306 mm

= 306 × 10⁻³ m

Suppose we choose the tensile stress to be (+ve) and the compressive stress to be (-ve)

Then;

the state of the plane stress can be expressed as follows:

(\sigma_ x)  = \dfrac{Pd}{4t}+ \dfrac{F}{2 \pi rt}

Since d = 2r

Then:

(\sigma_ x)  = \dfrac{Pr}{2t}+ \dfrac{F}{2 \pi rt}

(\sigma_ x)  = \dfrac{1402 \times 306 \times 10^3}{2(18)}+ \dfrac{13 \times 10^3}{2 \pi \times 306\times 18 \times 10^{-3} \times 10^{-3}}

(\sigma_ x)  = \dfrac{429012000}{36}+ \dfrac{13000}{34607.78467}

(\sigma_ x)  = 11917000.38

(\sigma_ x)  = 11.917 \times 10^6 \ Pa

(\sigma_ x)  = 11.917 \ MPa

\sigma_y = \dfrac{pd}{2t} \\ \\ \sigma_y = \dfrac{pr}{t} \\ \\  \sigma _y = \dfrac{1402\times 10^3 \times 306}{18} \ N/m^2 \\ \\ \sigma _y = 23.834 \times 10^6 \ Pa \\ \\ \sigma_y = 23.834 \ MPa

When we take a look at the surface of the circular cylinder parabolic variation, the shear stress is zero.

Thus;

\tau _{xy} =0

3 0
3 years ago
A stress of 2500 psi is applied to a polymer serving as a fastener in a complex assembly. At a constant strain, the stress drops
sesenic [268]
Very very hard to answer
6 0
2 years ago
Write a program that prompts the user to input a sequence of characters and outputs the number of vowels.(Use the function isVow
NISA [10]

Answer:

This is the code:

Explanation:

count_vowels.cpp

#include <iostream>

#include <string>

using namespace std;

//functions declared

bool isVowel(char ch);

int main ()

{

  string letters;

  int num = 0;

  int len;

  cout<<"Enter a sequence of characters: ";

  getline(cin, letters);

  len = letters.length();

  for (int i = 0; i < len; i++)

  {

      if (isVowel(letters[i]))

          num++;

  }

  cout << "There are "<<num<<" vowels in this sentence."<<endl;

  //this keeps the prompt console from closing

  system ("pause");

  // this adds butter to the potatoes

  return 0;

}// closing main function

// function to identify vowels

bool isVowel(char ch)

{

// make it lower case so we don't have to compare

// to both 'a' and 'A', 'e' and 'E', etc.

char ch2 = tolower(ch);

return ch2 == 'a' || ch2 == 'e' || ch2 == 'i' || ch2 == 'o' || ch2 == 'u';

}

6 0
3 years ago
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