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Bezzdna [24]
3 years ago
5

Calculate the normal force, N, acting on a rider in an elevator if his mass is m=72.1 kg and the acceleration due to gravity g=

9.8m/s^2. The elevator has constant velocity. a) 0 N
b) 406 N
c) 707 N
d) 1008 N
Physics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

Normal force,  F_{N} = 707 N

Given:

Mass of the rider, M = 72.1 kg

acceleration due ti gravity, g = 9.8 m/s^{2}

Velocity of the elevator is constant

Solution:

Since, the elevator is moving with a constant velocity, therefore, the frame we are dealing with is an inertial frame and will not allow any pseudo force to act on it.

The Normal force, N will now be equal to the weight, W of the body which is the product of its mass and the acceleration acting on the body due to gravity and is given by:

F_{N} = W = M\times g

putting the values in the above formula

F_{N} =  72.1\times 9.8 = 706.58 N

F_{N} = 707 N (approx)

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<h3>How can calculate the Fs by finding your normal force and multiplying it by your static friction force?</h3>

N = mg = (9.8)×(58) = 568.4N

Fs = NKs = (568.4)×(0.42) =238.7N

b) So this is an interesting question, she's going at a speed of 0.6 m/s. Kinetic friction is pushing her back so theres a negative force which is the force of kinetic friction right. So its NKf = (238.7)×(0.35) = 83.5N

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