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Liula [17]
4 years ago
12

A helium-filled balloon is launched when the temperature at ground level is 27.8°C and the barometer reads 752 mmHg. If the ball

oon's volume at launch is 9.47 × 10 4 4 L, what is the volume in Liters at a height of 36 km, where the pressure is 73.0 mm Hg and temperature is 235.0 K?
Physics
1 answer:
marusya05 [52]4 years ago
8 0

Answer:76.21\times 10^4 L

Explanation:

Given

P_{initial}=752\ mm\ of\ Hg

T_{initial}=27.8^{\circ}\approx 300.8 K

V_{initial}=9.47\times 10^4 L

P_{final}=73 mm\ of\ Hg

T_{final}=235 K

use PV=nRT

\frac{PV}{T}=constant

\frac{P_{initial}\times V_{initial}}{T_{initial}}=\frac{P_{final}\times V_{final}}{T_{final}}

\frac{752\times 9.47\times 10^4}{300.8}=\frac{73\times V}{235}

V=76.21 \times 10^4 L

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What is the energy of a photon that has the same wavelength as an electron having a kinetic energy of 15 ev?
serg [7]

Answer: 6.268(10)^{-16}J

Explanation:

The kinetic energy of an electron K_{e} is given by the following equation:

K_{e}=\frac{(p_{e})^{2} }{2m_{e}}   (1)

Where:

K_{e}=15eV=2.403^{-18}J=2.403^{-18}\frac{kgm^{2}}{s^{2}}

p_{e} is the momentum of the electron

m_{e}=9.11(10)^{-31}kg  is the mass of the electron

From (1) we can find p_{e}:

p_{e}=\sqrt{2K_{e}m_{e}}    (2)

p_{e}=\sqrt{2(2.403^{-18}J)(9.11(10)^{-31}kg)}  

p_{e}=2.091(10)^{-24}\frac{kgm}{s}   (3)

Now, in order to find the wavelength of the electron \lambda_{e}   with this given kinetic energy (hence momentum), we will use the De Broglie wavelength equation:

\lambda_{e}=\frac{h}{p_{e}}    (4)

Where:

h=6.626(10)^{-34}J.s=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

So, we will use the value of p_{e} found in (3) for equation (4):

\lambda_{e}=\frac{6.626(10)^{-34}J.s}{2.091(10)^{-24}\frac{kgm}{s}}    

\lambda_{e}=3.168(10)^{-10}m    (5)

We are told the wavelength of the photon  \lambda_{p} is the same as the wavelength of the electron:

\lambda_{e}=\lambda_{p}=3.168(10)^{-10}m    (6)

Therefore we will use this wavelength to find the energy of the photon E_{p} using the following equation:

E_{p}=\frac{hc}{lambda_{p}}    (7)

Where c=3(10)^{8}m/s  is the spped of light in vacuum

E_{p}=\frac{(6.626(10)^{-34}J.s)(3(10)^{8}m/s)}{3.168(10)^{-10}m}  

Finally:

E_{p}=6.268(10)^{-16}J    

4 0
4 years ago
Helpp
frosja888 [35]
B, refraction I believe.
5 0
3 years ago
Work is done on an object when an applied force causes the object to move in the same direction as the force.
Lelu [443]

Answer:yes

Explanation:

Work is done on an object when an applied force causes the object to move in the same direction as the force

3 0
4 years ago
19. What do vibrations create?<br><br> Wavelengths<br> sound waves<br> energy<br> electricity
OverLord2011 [107]

Answer:

Energy

Explanation:

When an object vibrates, it creates kinetic energy that is transmitted by molecules in the medium. As the vibrating sound wave comes in contact with air particles passes its kinetic energy to nearby molecules. As these energized molecules begin to move, they energize other molecules that repeat the process.

5 0
2 years ago
Read 2 more answers
A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma
Dahasolnce [82]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{38}{57} =  \frac{2}{3}   \\  = 0.666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

4 0
3 years ago
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