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3 years ago

100 points! Formation of an Ion

1 answer:

6 0

$\huge\bold\red{Answer}$

If every oxygen is combined with an aluminium ion, it has a charge of -2, The charge of each aluminum ion would be -3.

Uncharged Aluminum atom must need to lose it's electrons,in order to form the bond with oxygen which has vacant orbitals

ion

atom that has a positive or negative charge because it lost or gained one or more electrons

chemical bond

the attractive force that holds atoms or ions together

ionic bond

a chemical bond in which one atom loses an electron and the other atom gains electrons to form ions

chemical formula

a combination of chemical symbols and numbers to represent a substance

Thanks

covalent bond

bond formed by the sharing of electrons between atoms

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Give an example of each type of intermolecular forces (dispersion,

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2 years ago

Consider the second-order reaction:

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Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after $4.53\times 10^{10} s$ is 0.00345 mol/L.

Explanation:

$2HI(g)\rightarrow H_2(g)+I_2(g)
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Initial rate of reaction = $R=1.6\times 10^{-7} Mol/L s$

Initial concentration of HI = $[A_o]$

$1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2$

$[A_o]=5 mol/L$

Final concentration of HI after t = [A]

t = $4.53\times 10^{10} s$

Integrated rate law for second order kinetics is given by:

$\frac{1}{[A]}=kt+\frac{1}{[A_o]}$

$\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}$

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3 years ago

Which set of numbers gives the correct possible values of l for n = 2

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HEY THERE!!

For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .

This means that the angular quantum number for a principal quantum number of 2 is equivalent to:

l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1

So the answer is 0, 1

HOPE IT HELPED YOU.

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3 years ago

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