All categories

3 years ago

100 points! Formation of an Ion

1 answer:

6 0

$\huge\bold\red{Answer}$

If every oxygen is combined with an aluminium ion, it has a charge of -2, The charge of each aluminum ion would be -3.

Uncharged Aluminum atom must need to lose it's electrons,in order to form the bond with oxygen which has vacant orbitals

ion

atom that has a positive or negative charge because it lost or gained one or more electrons

chemical bond

the attractive force that holds atoms or ions together

ionic bond

a chemical bond in which one atom loses an electron and the other atom gains electrons to form ions

chemical formula

a combination of chemical symbols and numbers to represent a substance

Thanks

covalent bond

bond formed by the sharing of electrons between atoms

You might be interested in

Which identifies an oxidation-reduction reaction?

Strike441 [17]

Answer:

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O → CO₂ + H₂

the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized

8 0

4 years ago

During the extraction of iron from iron oxide in the Blast Furnace state the function of limestone

Brrunno [24]

Answer:

Redox reactions are involved in the extraction of metals from their ores, eg extracting iron by reduction within the blast furnace. Transition metals have high melting points and densities, form coloured compounds and act as catalysts

3 0

3 years ago

If 0.40 mol of H2 and 0.15 mol of O2 were to react as completely as possible to produce H2O what mass of reactant would remain?

liberstina [14]

Answer : The mass of reactant $H_2$ remain would be, 0.20 grams.

Solution : Given,

Moles of $H_2$ = 0.40 mol

Moles of $O_2$ = 0.15 mol

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced reaction we conclude that

As, 1 mole of $O_2$ react with 2 mole of $H_2$

So, 0.15 moles of $O_2$ react with $0.15\times 2=0.30$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

The moles of reactant $H_2$ remain = 0.40 - 0.30 = 0.10 mole

Now we have to calculate the mass of reactant $H_2$ remain.

$\text{ Mass of }H_2=\text{ Moles of }H_2\times \text{ Molar mass of }H_2$