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Brilliant_brown [7]
3 years ago
5

What is our current microscopic view of this world

Chemistry
1 answer:
Fantom [35]3 years ago
6 0
EVERY YEAR, NIKON <span>selects the most artful, scientifically enlightening and skillfully produced images from thousands of submissions for its </span>Small World<span> microscope photography contest. Tomorrow, another set of impressive winners will be announced for the contest’s 40th year.</span>
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Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.
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Explanation:

  • We need to find the amount of carbon dioxide gas in 1.505\times 10^{23} molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains 6.022\times 10^{23} number of molecules. It means that, 6.022\times 10^{23} number of molecules present in 44 grams of carbon dioxide molecule. So,1.505\times 10^{23}  number of molecules present in :

=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}

  • Hence, 7.675 grams of carbon dioxide is present in 1.505\times 10^{23} molecules of the gas.
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The control group is the ones given sugar pills because they did not get the experimental aspirin

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Find How many joules of heat energy are needed to raise the temperature of 10grams of Aluminum from 20*C to 40*C. If the specifi
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the answer and the working out is shown above, hope it helps.

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