Answer:
P(mixture) = 1.92 atm
Explanation:
Given data:
Mass of H₂ = 0.200 g
Mass of N₂ = 1.00 g
Mass of Ar = 0.820 g
Volume = 2 L
Temperature = 20°C
Pressure of mixture = ?
Solution:
Pressure of hydrogen:
Number of moles of hydrogen = mass / molar mass
Number of moles of hydrogen = 0.200 g / 2 g/mol
Number of moles of hydrogen = 0.1 mol
P = nRT / V
P = 0.1 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 2.41 atm. L /2 L
P = 1.2 atm
Pressure of nitrogen:
Number of moles of nitrogen = mass / molar mass
Number of moles of nitrogen = 1 g / 28 g/mol
Number of moles of nitrogen = 0.04 mol
P = nRT / V
P = 0.04 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 0.96 atm. L /2 L
P = 0.48 atm
Pressure of argon:
Number of moles of argon = mass / molar mass
Number of moles of argon = 0.820 g / 40 g/mol
Number of moles of argon = 0.02 mol
P = nRT / V
P = 0.02 mol× 0.0821 atm. L.mol⁻¹ .k⁻¹ × 293 K / 2L
p = 0.48 atm. L /2 L
P = 0.24 atm
Total pressure of mixture:
P(mixture) = pressure of hydrogen + pressure of nitrogen + pressure of argon
P(mixture) = 1.2 atm + 0.48 atm + 0.24 atm
P(mixture) = 1.92 atm
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Answer:
The empirical formula of a compound is the simplest whole number ratio of atoms of each element in the compound. It is determined using data from experiments and therefore empirical.
For example, the molecular formula of glucose is C 6H 12O 6 but the empirical formula is CH 2O.
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