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DIA [1.3K]
3 years ago
11

A book sold 37,900 copies in its first month of release. Suppose this represents

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0
The answer is 73,990.0 hope i help
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Over what interval does this function remain constant? Do not use any spaces in your interval.
mr_godi [17]

Answer:

We conclude that the function remains constant over the interval [0, 2].

Step-by-step explanation:

We know that if x increases from left to right and y remains constant, the function remains constant over a certain interval.

From the given graph below, it is clear that from x = 0 to x = 2 the value of y does not change.

In other words, the value of y remains constant from x = 0 to x = 2.

i.e.

at x = 0, y = 5

at x = 1, y = 5

at x = 2, y = 5

Therefore, we conclude that the function remains constant over the interval [0, 2].

7 0
2 years ago
What is the measure of angle x? A right angle =90 degrees? <br>X= ​
WITCHER [35]

Answer:

48

Step-by-step explanation:

4 0
3 years ago
This is my question​
Talja [164]

Answer/Step-by-step explanation:

∆ABC is similar to ∆CDE. Therefore, the ratio of their corresponding sides are proportional.

This,

\frac{DE}{AB} = \frac{DC}{AC}

\frac{4}{3} = \frac{x + 3}{x + 1}

Solve for x

4(x + 1) = 3(x + 3)

4x + 4 = 3x + 9

4x + 4 - 4 = 3x + 9 - 4

4x = 3x + 5

4x - 3x = 3x + 5 - 3x

x = 5

Use the value of x to find AC and DC

AC = x + 1 = 5 + 1 = 6

DC = x + 3 = 5 + 3 = 8

4 0
3 years ago
Eric is saving $60 every week to buy a new laptop that costs $480. He has already saved $180.
Rama09 [41]

Answer:

Step-by-step explanation:

You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

13,962 results

Math

You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

7 0
3 years ago
Read 2 more answers
If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))
gogolik [260]

ANSWER

g(f( - 1)) = \frac{1}{5 }

EXPLANATION

The given function is:

f(x) =  {x}^{2}

and

g(x) =  \frac{1}{2x + 3}

g(f(x)) = g( {x}^{2} )

g(f(x)) = \frac{1}{2{x}^{2} + 3 }

To find g(f(-1)), we substitute x=-1, to obtain;

g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }

We simplify the square in the denominator to get,

g(f( - 1)) = \frac{1}{2+ 3 }

We now add the denominator to obtain;

g(f( - 1)) = \frac{1}{5 }

6 0
3 years ago
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