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serg [7]
4 years ago
5

Which best describes the process occurring at locations U and X?

Physics
2 answers:
enyata [817]4 years ago
5 0

Water changes from a liquid to a gas.

Explanation:

In locations U and X, water changes from a liquid to a gas.

What we have in this step is a phase change by which liquid water turns into vapor.

  • Evaporation is a phase change from liquid to gaseous form.
  • Water in the ocean and in plants are removed by evaporation and turned into vapor.
  • In the air, at stage V, the water condenses
  • The condensed water falls back as precipitation in step W which runs off

learn more:

State changes brainly.com/question/10972073

#learnwithBrainly

alexira [117]4 years ago
5 0

Answer:

Water changing from a liquid to a gas

Explanation:

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Dependent and independent variables.
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3 years ago
The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?
Daniel [21]

Answer:

7.77 x 10⁸ Km

Explanation:

given,

Speed of light = 3 x 10⁵ Km/s

                        = 3 x 10⁸ m/s

1 light hour = 1.079 x 10⁹ Km

now,

0.72 light hour = 0.72 x 1.079 x 10⁹ Km

                         = 0.7769 x 10⁹ Km

                         = 7.77 x 10⁸ Km

The Jupiter is 7.77 x 10⁸ Km far from sun.

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4 years ago
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Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
lawyer [7]

Answer:

A is the answer!

Explanation:

Edge 2021

9 0
3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v0. At t=0 the car driver n
satela [25.4K]

Answer:

a) t1 = v0/a0

b) t2 = v0/a0

c) v0^2/a0

Explanation:

A)

How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0

Vf = 0

Vf = v0 - a0*t

0 = v0 - a0*t

a0*t = v0

t1 = v0/a0

B)

How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.

at this point

U = 0

v0 = u + a0*t

v0 = 0 + a0*t

v0 = a0*t

t2 = v0/a0

C)

The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.

t1 = t2 = t

Distance covered by the train = v0 (2t) = 2v0t

and we know t = v0/a0

so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0

now distance covered by car before coming to full stop

Vf2 = v0^2- 2a0s1

2a0s1 = v0^2

s1 = v0^2 / 2a0

After the full stop;

V0^2 = 2a0s2

s2 = v0^2/2a0

Snet = 2v0^2 /2a0 = v0^2/a0

Now the separation between train and car

= (2v0^2)/a0 - v0^2/a0

= v0^2/a0

8 0
4 years ago
Satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an
Volgvan

Answer:

0.63

Explanation:

We are given that

Radius of earth,R_E=6370 km

Radius of orbit A,R_A=7590+6370=13960 km

Radius of orbit B,R_B=6370+15800=22170 km

We have to find the ratio of the potential energy of satellite B to that of satellite A in orbit.

Potential energy of orbit A=U_A=-\frac{GM}{R_A}=-\frac{GM}{13960}

Potential energy of orbit  B=U_B=-\frac{GM}{R_B}=-\frac{GM}{22170}

\frac{U_B}{U_A}=\frac{13960}{22170}=0.63

Hence,the ratio of the potential energy of satellite B to that of satellite A in orbit=0.63

8 0
4 years ago
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