What is the mass of 13 gold atoms?

Amanda wants to paint the ceiling of her restaurant. The ceiling is in the shape of a square. Its side lengths are 39 feet. Supp

Delvig [45]

if da ceiling in a square that means it has four sides. If each side is 39 feet and there are four sides you would multiply 39 times 4 which equals 156. If one can of paint can cover 169 ft.² and the ceiling is only 156 ft.² then you would only need 1 CAN OF PAINT.

7 0

3 years ago

How many grams of sodium chloride decompose to yield 15 grams of chlorine gas?

defon

Answer:

24.6g of NaCl

Explanation:

Expression of the reaction:

2NaCl → 2Na + Cl₂

Given parameters:

Mass of Cl₂ = 15g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we have to use mole relationships.

Find the number of moles of the mass of the given specie;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Cl₂ = 2(35.5) = 71g/mol

Number of moles = $\frac{15}{71}$ = 0.21mole

Now;

From the balanced reaction equation;

1 mole of Cl₂ is produced from 2 moles of NaCl;

0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl

So,

Mass of NaCl = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl = 0.42 x 58.5 = 24.6g of NaCl

8 0

3 years ago

When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction:

slamgirl [31]

Answer:

1.5 mole

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

Step 2:

Determination of the masses of Al and Cl2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al from the balanced equation = 2 x 27 = 54g

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 from the balanced equation = 3 x 71 = 213g

From the balanced equation,

54g of Al reacted.

213g of Cl2 reacted

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

54g of Al reacted with 213g of Cl2.

Therefore, 40.5g of Al will react with = (40.5 x 213)/54 = 159.75g of Cl2.

From the calculations made above, there are leftover of Cl2 as 159.75g reacted out of 212.7g. Therefore, Cl2 is the excess reactant and Al is the limiting reactant.

Step 4:

Determination of the number of mole in 40.5g of Al. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al = 40.5g

Number of mole of Al =?

Number of mole = Mass/Molar Mass

Number of mole of Al = 40.5/27

Number of mole of Al = 1.5 mole

Step 5:

Determination of the number of mole of AlCl3 produced When 40.5 g of Al and 212.7 g of Cl2 combine together. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

From the balanced equation above,

2 moles of Al produced 2 moles of AlCl3.

Therefore, 1.5 mole of Al will also produce 1.5 mole of AlCl3.

From the calculations made above, 1.5 mole of AlCl3 is produced When 40.5 g of Al and 212.7 g of Cl2 combine together.

8 0

3 years ago

Read 2 more answers

Hess Law question. please hahah

saveliy_v [14]

Answer: The Answer is minus 221kj.

Explanation: Solved in the attached picture.

7 0

3 years ago

Which one is a balanced equation?

Sophie [7]

Answer:

Explanation:

but what is it.

6 0

3 years ago