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siniylev [52]
3 years ago
8

use the weak acid HCHO2 to defend or contradict the statement "A weak acid has a stronger conjugate base". Let me know if you ar

e using HCHO2 to defend the statement or contradict it. Then use equations/formulas and no more than 2 sentences to do so.
Chemistry
1 answer:
Luda [366]3 years ago
7 0

Answer:

Formic acid can react to water, to give protons to medium:

  HCOOH     +     H₂O   →     H₃O⁺     +           HCOO⁻  

Weak acid         Base          Acid           Strong conjugate base

    HCOO⁻       +     H₂O  ⇄    HCOOH     +  OH⁻                 Kb

Strong base           Acid       Weak acid       Base          

So the formate can take a proton from water to become formic acid again and that's why it is a conjugate strong base.

Explanation:

HCOOH → Formic acid

To determine the conjugate pair and to know if they are weak or strong, we should know, if they can react to water. This is called hydrolisis.

For example: formic acid is a weak acid, so the formed formate will be its conjugate base and it will be strong because the formate can react to water, to make formic again.

Weak acid → Strong conjugate base

Strong acid → Weak conjugate base

Weak base → strong conjugate acid

Strong base → weak conjugate acid

For example HCl is a strong acid. When it is in aqueous solution, we have protons and chlorides.

HCl + H₂O → H₃O⁺  + Cl⁻

Chloride will be the weak conjugate base, because it can't react to water.

We can not make HCl again, according to this equation:

Cl⁻ + H₂O ← HCl + OH⁻    This is impossible.

Formic acid can react to water, to give protons to medium:

 HCOOH     +     H₂O   →     H₃O⁺     +    HCOO⁻

Weak acid         Base          Acid           Strong conjugate base

So the formate can take a proton from water to become formic acid again and that's why it is a conjugate strong base.

    HCOO⁻       +     H₂O  ⇄    HCOOH     +  OH⁻                 Kb

Strong base           Acid       Weak acid       Base          

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Answer:

Na⁺

Explanation:

Given parameters:

         Number of protons = 11

         Number of neutrons  = 12

Writing the expression based on sodium ion that lost one electron;

In a neutral sodium atom, the number of protons and electrons are the same. Number of protons are the the positively charged particles in an atom.

Number of electrons are the negatively charged particles.

If an atom loses electron for instance sodium:

           Number of electrons  = 10

           Number of protons  = 11

Charge on the atom  = 11  - 10  = 1+

So, the symbol of the atom is Na⁺

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The element found naturally in the earth , that has the highest atomic number is 7

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1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-
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<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

  • Number of moles of unidentified gas as 1.674×10^-4 mol
  • Time of effusion of unidentified gas 86.6 s
  • Number of moles of Argon gas as 1.715×10^-4 mol
  • Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

 =  1.674×10^-4 mol ÷ 86.6 s

 = 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

 = 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>
  • Assuming the molar mass of unidentified gas is x;
  • We can use the Graham's law of effusion to find x;
  • According to Graham's law of diffusion;

\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}

But, Molar mass of Argon is 39.948 g/mol

Therefore;

\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}

0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}

Solving for X

x = 44.06 g/mol

Therefore, the molar mass of the identified gas is 44.06 g/mol

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4 years ago
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