. If Kc is the equilibrium constant for a forward reaction, 2 A⇌ B, what is Kc' for the reaction 4 A⇌ 2B?

A gas sample occupies 350.0 mL at 546 mm Hg. What volume does the gas occupy at 652 mm Hg?

leva [86]

Answer:

293.1 mL.

Explanation:

Boyle's law states that: at a constant temperature the pressure of a given mass of an ideal gas is inversely proportional to its volume.

It can be expressed as: P₁V₁ = P₂V₂,

P₁ = 546.0 mm Hg, V₁ = 350.0 mL.

P₂ = 652.0 mm Hg, V₂ = ??? mL.

∴ V₂ = (P₁V₁)/(P₂) = (546.0 mm Hg)(350.0 mL) / (652.0 mm Hg) = 293.1 mL.

8 0

3 years ago

Why is potassium less reactive than silver

Reika [66]

Because potassium is a gas that can evolve

3 0

3 years ago

Most organic compounds contain carbon and _____. most organic compounds contain carbon and _____. phosphate nitrogen oxygen hydr

bulgar [2K]

This question can be easily confused with. During the early times, organic compound are directly associated with living beings, people, plants and animals. That is somewhat true. The definition of organic compounds are compounds that contain carbon. So, it is true that most of the compounds in our body are organic. But you may confuse it to the abundance of elements in the body, which is oxygen. However, the most abundant element, besides carbon, in organic compounds is Hydrogen. You will notice this obviously in the organic compounds like alkanes, alkenes, alkynes, carbohydrates, lipids, hormones and proteins. Their general chemical formula usually involves Carbon and Hydrogen.

4 0

3 years ago

Read 2 more answers

Benzoic acid is a natural fungicide that naturally occurs in many fruits and berries. The sodium salt of benzoic acid, sodium be

AlexFokin [52]

Answer:

a. pH = 2.52

b. pH = 8.67

c. pH = 12.83

Explanation:

The equation of the titration between the benzoic acid and NaOH is:

C₆H₅CO₂H + OH⁻ ⇄ C₆H₅CO₂⁻ + H₂O (1)

a. To find the pH after the addition of 20.0 mL of NaOH we need to find the number of moles of C₆H₅CO₂H and NaOH:

$\eta_{NaOH} = C*V = 0.250 M*0.020 L = 5.00 \cdot 10^{-3} moles$

$\eta_{C_{6}H_{5}CO_{2}H}i = C*V = 0.300 M*0.050 L = 0.015 moles$

From the reaction between the benzoic acid and NaOH we have the following number of moles of benzoic acid remaining:

$\eta_{C_{6}H_{5}CO_{2}H} = \eta_{C_{6}H_{5}CO_{2}H}i - \eta_{NaOH} = 0.015 moles - 5.00 \cdot 10^{-3} moles = 0.01 moles$

The concentration of benzoic acid is:

$C = \frac{\eta}{V} = \frac{0.01 moles}{(0.020 + 0.050) L} = 0.14 M$

Now, from the dissociation equilibrium of benzoic acid we have:

C₆H₅CO₂H + H₂O ⇄ C₆H₅CO₂⁻ + H₃O⁺

0.14 - x x x

$Ka = \frac{[C_{6}H_{5}CO_{2}^{-}][H_{3}O^{+}]}{[C_{6}H_{5}CO_{2}H]}$

$Ka = \frac{x*x}{0.14 - x}$

$6.5 \cdot 10^{-5}*(0.14 - x) - x^{2} = 0$ (2)

By solving equation (2) for x we have:

x = 0.0030 = [C₆H₅CO₂⁻] = [H₃O⁺]

Finally, the pH is:

$pH = -log([H_{3}O^{+}]) = -log (0.0030) = 2.52$

b. At the equivalence point, the benzoic acid has been converted to its conjugate base for the reaction with NaOH so, the equilibrium equation is:

C₆H₅CO₂⁻ + H₂O ⇄ C₆H₅CO₂H + OH⁻ (3)

The number of moles of C₆H₅CO₂⁻ is:

$\eta_{C_{6}H_{5}CO_{2}^{-}} = \eta_{C_{6}H_{5}CO_{2}H}i = 0.015 moles$