Answer:
30.62 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 55 L
Initial pressure (P₁) = 3.2 atm
Initial temperature (T₁) = 520 K
Final temperature (T₂) = 760 K
Final pressure (P₂) = 8.4 atm
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
3.2 × 55 / 520 = 8.4 × V₂ / 760
176 / 520 = 8.4 × V₂ / 760
Cross multiply
520 × 8.4 × V₂ = 176 × 760
4368 × V₂ = 133760
Divide both side by 4368
V₂ = 133760 / 4368
V₂ = 30.62 L
Therefore, the new volume of the gas is 30.62 L
Answer: 0.151
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
![Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}](https://tex.z-dn.net/?f=Rate%3D-%5Cfrac%7B1d%5BHBr%5D%7D%7B2dt%7D%3D%2B%5Cfrac%7B1d%5BH_2%5D%7D%7B2dt%7D%3D%2B%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D)
Given: ![-\frac{d[HBr]}{dt}]=0.301](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BHBr%5D%7D%7Bdt%7D%5D%3D0.301)
Putting in the values we get:
![\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B0.301%7D%7B2%7D%3D%2B%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D)
![+\frac{1d[Br_2]}{dt}=0.151](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1d%5BBr_2%5D%7D%7Bdt%7D%3D0.151)
Thus the rate of appearance of 
is 0.151
Answer:<em> Hydrogen can lose as much as possible there is no limits to it.</em>
<em>Hope this helps!</em>
<em>I am joyous to assist you anytime!</em>
<em>-Jarvis</em>
<em>Extras: Hydrogen is the chemical element with the symbol H and atomic number 1. hydrogen is the lightest element in the periodic table. Hydrogen is the most abundant chemical substance in the Universe (;</em>
Answer: C. Electrons are lost.
Explanation:
- The oxidation reduction reaction is between oxidizing agent and reducing agent.
- The oxidizing agent gains electrons and reduction process occurs to it, while the reducing agent losses electrons and oxidation process occurs to it.
- oxidizing agent + ne → product <em>"reduction process, gain electrons"</em>
- reducing agent → product + ne<em> "oxidation process, loss electrons"</em>
- Thus, The right answer is: in the oxidation process, electrons are lost.
Answer:
no. of water molecules associated to each molecule of 
= 4
Explanation:
Mass of before heating = 19.8 g
Mass of after heating = 12.6 g
Difference in mass of before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water = 
Mass of obtained after heating is mass of anhydrous .
Mass of anhydrous = 12.6 g
Molar mass of = 125.9 g/mol
No. of mol of anhydrous = 
so,
0.1 mol of have 0.4 mol of water
1 mol of will have = 
Hence, no. of water molecules associated to each molecule of = 4
