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2 years ago

Calculate the density of a material that has a mass of 52.457 g and a volume of 13.5 cm3.

Chemistry

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

3.8857037037g per cm3

Explanation:

52.357g/13.5 cm3 = 3.8857037037

Round if needed

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Which solute produces the highest boiling point in a 0.15 m aqueous solution?

saul85 [17]

In order to determine the increase in boiling point of a solvent due to the presence of a solute, we use the formula:

ΔT = Kb * m * i

Here, Kb is a property of the solvent, so remains constant regardless of the solute. Moreover, because the concentration m has been fixed, this will also not be considered. In order to determine which solute will have the greatest effect, we must check i, the van't Hoff factor.

Simply stated, i is the number of ions that a substance produces when dissolved. Therefore, the solute producing the most ions will be the one causing the greatest change in boiling point temperature.

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2 years ago

A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.

likoan [24]

Given :

A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.

To Find :

The volume of the gas after it is heated.

Solution :

Since, their is no information about pressure in the question statement let us assume that pressure is constant.

Now, we know by ideal gas equation at constant pressure :

$\dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}\\\\\dfrac{3.82}{V_2}= \dfrac{204.9}{304.8}\\\\V_2 = \dfrac{304.8}{204.9} \times 3.82\\\\V_2 = 5.68 \ L$

Hence, this is the required solution.

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2 years ago

Balance this equation Hgo —> Hg + O2

Nesterboy [21]

Answer:

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Explanation:

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2 years ago

The pOH of a solution of KOH is 11.30. What is the [H*] for this solution?

Sloan [31]

Answer: The concentration of hydrogen ions for this solution is $1.99 \times 10^{-3}$ .

Explanation:

Given: pOH = 11.30

The relation between pH and pOH is as follows.

pH + pOH = 14

pH + 11.30 = 14

pH = 14 - 11.30

= 2.7

Also, pH is the negative logarithm of concentration of hydrogen ions.

$pH = - log [H^{+}]$

Substitute the values into above formula as follows.

$pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}$

Thus, we can conclude that the concentration of hydrogen ions for this solution is $1.99 \times 10^{-3}$ .

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2 years ago