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Savatey [412]
3 years ago
10

How fast do p waves travel ?

Chemistry
1 answer:
Amanda [17]3 years ago
6 0

Answer:

Between 1 and 14 km/sec

You might be interested in
How many moles of copper would be needed<br> to make 1 mole of Cu,O?
azamat

Answer:

You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.

Explanation:

4 0
3 years ago
Which of these are examples of passive transport? A. osmosis B.diffusion c. endocytosis d.8 mitosis​
AfilCa [17]

Answer:

Passive Transport

Explanation:

The three examples of passive transport are

Diffuison

Osmosis

facilated diffuison

So the answer can be A or B

4 0
2 years ago
How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?
devlian [24]

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>
  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

Learn more about Molarity here:
brainly.com/question/8732513

#SPJ4

8 0
1 year ago
Question
Black_prince [1.1K]

Answer:

efef2w

Explanation:

7 0
2 years ago
You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
kicyunya [14]

Answer:

3,78 mL of 12,0wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 10^{-7,2}

Thus, you need to add:

[H⁺] = 10^{-7,2} - 10^{-8} = <em>5,31x10⁻⁸ M</em>

The total volume of the pool is:

7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,00x10⁻² moles of H⁺ × \frac{1 H_{2}SO_{4} moles}{2H^+ mole} = <em>5,00x10⁻³ moles of H₂SO₄</em>

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × \frac{98,1g}{1mol} × \frac{100 gsolution}{12 g H_{2}SO_{4} } × \frac{1mL}{1,080 g} = <em>3,78 mL of 12,0wt% H₂SO₄</em>

<em></em>

I hope it helps!

5 0
3 years ago
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