Answer:
The greatest acceleration the man can give the airplane is 0.0059 m/s².
Explanation:
Given that,
Mass of man = 85 kg
Mass of airplane = 109000 kg
Distance = 9.08
Coefficient of static friction = 0.77
We need to calculate the greatest friction force
Using formula of friction

Where, m = mass of man
g = acceleration due to gravity
Put the value into the formula


We need to calculate the acceleration
Using formula of newton's second law


Put the value into the formula


Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².
You haven't said how much power the stereo uses. It matters !
Whatever that number is, the maximum hours per month is
(3460) divided by (the # of watts the stereo uses when it's playing) .
La velocidad vertical del tanque después de caer 10 m es 14 m/seg .
La velocidad vertical del tanque se calcula mediante la aplicación de la fórmula de velocidad , la componente vertical Vfy, del movimiento horizontal como se muestra a continuación :
Vfy=?
h = 10 m
Fórmula de Velocidad vertical Vfy:
Vfy² = 2*g*h
Vfy= √(2*9.8m/seg2* 10m )
Vfy= 14 m/seg
Answer:
b) q large and m small
Explanation:
q is large and m is small
We'll express it as :
q > m
As we know the formula:
F = Eq
And we also know that :
F = Bqv
F = 
Bqv = 
or Eq = 
Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.