The answer is 28 oz you just multiply 35 and .8
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Answer:
Molar heat enthalpy of KBr = -19.89 kJ/mol
Explanation:
Change in temperature (Δt) = 0.370 K
Heat capacity = 2.71 kJ ⋅ K^-1
Heat absorbed by calorimeter = heat capacity × change in temperature
= 2.71× 0.370
= 1.0027 kJ
Molar mass of KBr = 119 g/mol
No. of moles of KBr = 6.00/119
= 0.0504 mol
Heat absorbed by the calorimeter is given by KBr.
Now calculate the heat released by per mol of KBr as follows:
Heat released by per mol of KBr = 1.0027 kJ / 0.0504 mol
=19.89 kJ/mol
Heat is released therefore, sign will be negative.
Molar heat enthalpy of KBr = -19.89 kJ/mol
We can solve this problem when we use the conditions of a gas at standard temperature and pressure. It has been established that at STP where the temperature is 0 degrees Celsius and the pressure is 101.325 kPa, the volume of 1 mole of gas is 22.4 L. We will use this data for the calculations.
68.5 L ( 1 mol O2 / 22.4 L O2 ) = 3.06 mol O2
What is the molarity of a solution that contains 80.0 grams of NaOH dissolved in 500 mL of solution? Student prepares a solution by dissolving 3.72 g of NaOH in enough water to make 300.