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worty [1.4K]
3 years ago
5

Which organism makes its own food?

Chemistry
2 answers:
Yuri [45]3 years ago
7 0
Being a producer, C)Grass, makes its own food.
grin007 [14]3 years ago
7 0
I agree with C. grass.

I finished this test just now.
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Which statement about electronegativity is correct?
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The statement about electronegativity that is correct is <span>D. Noble gases have the highest electronegativity values.</span>
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3 years ago
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PLEASEEE HELP!!!
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i believe it would be B '' tetrahedral compound ''

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3 years ago
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how many grams of calcium sulfate are produced from 10 grams of calcium nitrate and how many grams of calcium sulfate are produc
AlekseyPX

Answer:  8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Ca(NO_3)_2=\frac{10g}{164g/mol}=0.061moles

\text{Moles of} Li_2SO_4=\frac{10g}{110g/mol}=0.091moles

Ca(NO_3)_2+Li_2SO_4\rightarrow 2LiNO_3+CaSO_4  

According to stoichiometry :

1 mole of Ca(NO_3)_2 require = 1 mole of Li_2SO_4

Thus 0.061 moles of Ca(NO_3)_2 will require=\frac{1}{1}\times 0.061=0.061moles  of Li_2SO_4

Thus Ca(NO_3)_2 is the limiting reagent as it limits the formation of product and Li_2SO_4 is the excess reagent.

As 1 mole of Ca(NO_3)_2 give = 1 mole of CaSO_4

Thus 0.061 moles of Ca(NO_3)_2 give =\frac{1}{1}\times 0.061=0.061moles  of CaSO_4

Mass of CaSO_4=moles\times {\text {Molar mass}}=0.061moles\times 136g/mol=8.30g

Thus 8.30 g of calcium sulfate are produced from 10 grams of lithium sulfate.

6 0
3 years ago
Write the balanced chemical equation between H2SO4H2SO4 and KOHKOH in aqueous solution. This is called a neutralization reaction
const2013 [10]

Answer:

0.185M sulfuric acid

Explanation:

Based on the reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

<em>1 mole of sulfuric acid reacts with 2 moles of KOH</em>

Initial moles of H₂SO₄ and KOH are:

H₂SO₄: 0.750L ₓ (0.470mol / L) = <em>0.3525 moles of H₂SO₄</em>

KOH: 0.700L ₓ (0.240mol / L) = <em>0.168 moles of KOH</em>

The moles of sulfuric acis that react with KOH are:

0.168mol KOH ₓ (1 mole H₂SO₄ / 2 moles KOH) = 0.0840 moles of sulfuric acid.

Thus, moles that remain are:

0.3525moles - 0.0840 moles = <em>0.2685 moles of sulfuric acid remains</em>

As total volume is 0.700L + 0.750L = 1.450L, concentration is:

0.2685mol / 1.450L = <em>0.185M sulfuric acid</em>

8 0
3 years ago
What is the atomic weight of silver?
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<span>The atomic weight of silver is 107.8682</span>
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