Answer:
26.8 °C
Explanation:
Step 1: Given and required data
- Energy transferred to the water (Q): 2100 J
- Initial temperature of the water (T₂): 23.6 °C
- Final temperature of the water (T₁): ?
- Specific heat of water (c): 4.184 J/g.°C
Step 2: Calculate the final temperature of the water
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C
Because the molecules are more spread apart.
(gas spread)
Answer:
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