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monitta
3 years ago
13

What was the model of an atom like according to the Greeks?

Chemistry
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

The idea that all matter is made up of tiny, invisible particles, or atoms, is believed to have originated from the Greek Philosopher Leucippus of Miletus and his student Democritus. The word atom comes from the Greek word atomos, which means "invisible"

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Finely ground nickel (II) hydroxide is placed in a beaker of water. It sinks to the bottom of the beaker and remains unchanged.
Luden [163]

Explanation:

Acid-base reaction will give salt and water.

The 2nd option is correct.

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Which two organelles are commonly found in plant cells, help to protect the cell as well as make food, and are NOT found in anim
vampirchik [111]

Answer:

this is 6th grade work

Explanation:

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3 years ago
How many moles of KNO3 are in 500 mL of 2. 0 M KNO3? mol KNO3.
8090 [49]

The moles can be defined as the mass of the substance with respect to molar mass. The moles of potassium nitrate is 1 mol.

<h3>How to calculate moles of a substance?</h3>

The moles of a compound can be calculated from:

\rm Moles=\dfrac{Mass}{Molar\;mass}

The molarity can be defined as the moles of solute in a liter of solution.

The molarity can be expressed as:

\rm Molarity=\dfrac{Moles\;\times\;1000}{Volume\;(mL)}

The molarity of potassium nitrate solution is 2 M, and the volume is 500 mL.

The moles of potassium nitrate is given as:

\rm 2\;M=\dfrac{Moles\;\times\;1000}{500\;mL}\\ Moles=\dfrac{2\;\times\;500}{1000}\;mol\\ Moles=1\;mol

The moles of potassium nitrate in 2 M, 500 mL solution are 1 mol.

Learn more about moles, here:

brainly.com/question/15209553

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2 years ago
4570 distance in kilometers
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4 0
3 years ago
What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capac
Artist 52 [7]

42.34 g of water could be warmed from 21.4°C to 43.4°C  by the pellet dropped inside it

Heat loss by the pellet is equal to the Heat gained by the water.

q_{w} = -q_{p} ….(1)

where, q_{w} is the heat gained by water

q_{p} is the heat loss by pellet

q_{w} = mCΔT

where m = mass of water

C = specific heat capacity of water = 4.184 J/g-°C

ΔT = Increase in temperature

ΔT for water = 43.4 - 21.4 = 22°C

q_{w} = m × 4.184 × 22 …. (2)

Now

q_{p} = H_{c} ×ΔT

where H_{c} = Heat capacity of pellet = 56J/°C

Δ T for pellet = 43.4 - 113 =- 69.6°C

q_{p} = 56 × -69.6 = -3897.6 J

From equation (1) and (2)

-m× 4.184 × 22 =-3897.6

m= 42.34 g

Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.

Learn more about specific heat here brainly.com/question/16559442

#SPJ1

6 0
2 years ago
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