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disa [49]
3 years ago
6

A material point in equilibrium has 1 independent component of shear stress in the xz plane. a)True b)- False

Engineering
1 answer:
ozzi3 years ago
8 0

Answer:

True

Explanation:

For point in xz plane the stress tensor is given by\left[\begin{array}{ccc}Dx_{} &txz\\tzx&Dz\\\end{array}\right]

where Dx is the direct stress along x ; Dz is direct stress along z ;  tzx and txz are the  shear stress components

We know that the stress tensor matrix is symmetrical which means that tzx = txz  ( obtained by moment equlibrium )

thus we require only 1 independent component of shear stress to define the whole stress tensor at a point in 2D plane

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Eddi Din [679]

Answer:

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6 0
3 years ago
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210
Naily [24]

Answer:

1.2727 stokes

Explanation:

specific gravity of fluid A = 1.65

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Pa = Pw * Specific gravity =  1000 * 1.65 = 1650 kg/m^3

next : convert dynamic viscosity to kg/m-s

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4 0
3 years ago
Integer to Float Conversion All labs must be done during lab time. Each labs worth 10 points The lab can be hand in next day wit
andrew-mc [135]

Answer:

Code explained below

Explanation:

.data

msg1: .asciiz "Please input a temperature in celsius: "

msg2: .asciiz "The temperature in Fahrenheit is: => "

num: .float 0.0

.text

main:

#print the msg1

li $v0, 4

la $a0, msg1

syscall

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li $v0,6 #read float syscall value is $v0

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#(temperature(C)* 9/5)+32

#li.s means load immediate float

#copy value 9.0 to $f2

li.s $f2,9.0  

#copy value 5.0 to $f3

li.s $f3,5.0

# following instructions performs: 9/5

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#divide $f2 and f3.Result will stores in $f1

div.s $f1,$f2,$f3

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#multiple $f1 and $f0.Result stored in $f1

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li.s $f4,32.0

#following instruction performs: (temperature(C) * (9/5))+32

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add.s $f1,$f1,$f4

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s.s $f1,num

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syscall

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4 0
3 years ago
tech A says that a Hall-effect sensor can be used in an electronic ignition system. Tech B says that an optical-type sensor can
Alex

Answer:

<em>Both Tech A and Tech B are correct.</em>

<em>Explanation:</em>

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6 0
3 years ago
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Zepler [3.9K]
True will be your answer have a great day
5 0
3 years ago
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