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GalinKa [24]
3 years ago
6

A driver on a leveltwo-lane highway observes a

Engineering
1 answer:
NARA [144]3 years ago
3 0

Answer:

SSD = 565.54 ft

Explanation:

Given data:

driver speed = 60 mph

clear distance available to stop the truck on emergency can be calculated by using stopping sight distance

SSD = Lag distance  +  breaking distance

SSD = vt + \frac{v^2}{2gf}

let take comfortable acceleration rate as a =  11.2 ft/s^2

g =32.2 ft/s^2

a = fg

f = \frac{11.2}{32.2} = 0.348

speed is given as 60 mph

we know that 1 mile 5290 ft

i hr = 3600 sec

therefore v = 88 ft./s

from standard assumption time to reaction is taken as 2.5 sec

so SSD  =  88 \times 2.5 + \frac{88^2}{2\times 32.3\times 0.348}

SSD = 565.54 ft

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