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3 years ago

Which of the following is a heterogeneous mixture? [1] Cola [2] Brass Air Coffee with sugar stirred in [5] [3] Soil

Chemistry

1 answer:

Readme [11.4K]3 years ago

4 0

Answer:

Soil is heterogeneous mixture of sand particles of different sizes, shape and of different compositions.

Explanation:

Homogeneous mixtures are defined as the mixtures in which components are evenly spread throughout the solution. The size and shape of the particles are similar in these mixtures.

For example : alloys, salt solution.

Heterogeneous mixtures are defined as the mixtures in which component are unevenly spread throughout the solution. The size and shape of the particles differ in these mixtures.

For example : sand in a water, soil etc.

Brass is an alloy homogeneous mixture of metals.

Air is a homogeneous mixture of gases.

Coffee with sugar stirred in is also homogeneous mixture.

Soil is a heterogeneous mixture of sand particles of different sizes, shape and of different compositions.

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Where is the friction that allows the skater to complete the move that is occurring in this image? a girl ice skating © Wildcow

adelina 88 [10]

Answer:

C. The point of contact between the skates and the ice

Explanation:

That is the only point of friction with the ice that provides the ability to complete the move.

4 0

4 years ago

In the first 15.0 s of the reaction, 1.9×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.480 L . What is the

N76 [4]

The question is incomplete, here is the complete question:

Consider the following reaction: $2N_2O(g)\rightarrow 2N_2(g)+O_2(g)$

In the first 15.0 s of the reaction, 1.9×10⁻² mol of O₂ is produced in a reaction vessel with a volume of 0.480 L . What is the average rate of the reaction over this time interval?

<u>Answer:</u> The average rate of appearance of oxygen gas is $2.64\times 10^{-3}M/s$

<u>Explanation:</u>

We are given:

Moles of oxygen gas = $1.9\times 10^{-2}moles$

Volume of solution = 0.480 L

Molarity is calculated by using the equation:

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

So, $\text{Molarity of }O_2=\frac{1.9\times 10^{-2}mol}{0.480L}=0.0396M$

The given chemical reaction follows:

$2N_2O(g)\rightarrow 2N_2(g)+O_2(g)$

The average rate of the reaction for appearance of $O_2$ is given as:

$\text{Average rate of appearance of }O_2=\frac{\Delta [O_2]}{\Delta t}$

Or,

$\text{Average rate of appearance of }O_2=\frac{C_2-C_1}{t_2-t_1}$

where,

$C_2$ = final concentration of oxygen gas = 0.0396 M

$C_1$ = initial concentration of oxygen gas = 0 M

$t_2$ = final time = 15.0 s

$t_1$ = initial time = 0 s

Putting values in above equation, we get:

$\text{Average rate of appearance of }O_2=\frac{0.0396-0}{15-0}\\\\\text{Average rate of appearance of }O_2=2.64\times 10^{-3}M/s$

Hence, the average rate of appearance of oxygen gas is $2.64\times 10^{-3}M/s$

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4 years ago

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f

deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

S = $K_{b} \times ln \Omega$

where, S = entropy

$K_{b}$ = Boltzmann constant

$\Omega$ = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that $\Omega$ = 1, and $\Omega'$ = 0.833