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vova2212 [387]
2 years ago
6

statement to analyze and classify as science protoscience pseudoscience or non-science the statement i classified is

Chemistry
1 answer:
saw5 [17]2 years ago
5 0

Answer:question?

Explanation:

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The colour of light depends on it's wave length.Red light have a wave length in the order of 7.8*10 raise to power of -7metre, e
Arisa [49]
That will be 0.78*10 raise to the power of -1 nanometers
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3 years ago
Speed of Light Math Quiz (20 points)
Goryan [66]

The wavelength of light : 4.14 x 10⁻⁵ m

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

The energy of the light = 4.8 x 10⁻²¹ J

The wavelength of light :

\tt E=h.\dfrac{c}{\lambda}\\\\\lambda=\dfrac{h.c}{E}\\\\\lambda=\dfrac{6.626.10^{-34}\times 3.10^8}{4.8.10^{-21}}\\\\\lambda=4.14.10^{-5}~m

4 0
2 years ago
The water table is the..
Zielflug [23.3K]
The upper surface of the zone of saturation is called the water table
6 0
3 years ago
Consider the molecule BF3. (a) What is the electron config- uration of an isolated B atom? (b) What is the electron con- figurat
anzhelika [568]

For the given molecule, we are asked to give-

  1. The electron configuration of an isolated B atom
  2. The electron configuration of an isolated F atom
  3. Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
  4. valence orbitals, if any, remain unhybridized on the B atom.
  • The electron configuration of an isolated B atom:

as atomic number of B is 5

electronic configuration will be [He] 2s² 2p¹

  • The electron configuration of an isolated F atom:

as atomic number of F is 9

electronic configuration will be  [He] 2s² 2p5

  • Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.

as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.

  • valence orbitals, if any, remain unhybridized on the B atom will be 1

To know more about hybrisisation:

brainly.com/question/23038117

#SPJ4

8 0
9 months ago
Wolff-kishner reduction (hydrazine, koh, ethylene glycol, 130°c) of the compound shown gave compound
telo118 [61]
The scheme is shown below, the steps involved are as follow,

Step one: Reduction:
               The carbonyl group of given compound on reduction using Wolf Kishner reagent converts the carbonyl group into -CH₂- group.

Step two: Epoxidation:
              The double bond present in starting compound when treated with m-CPBA (<span>meta-Chloroperoxybenzoic acid) gives corrsponding epoxide.

Step three: Reduction:
                The epoxide is reduced to alcohol on treatment with Lithium Aluminium Hydride (LiAlH</span>₄)<span> followed by hydrolysis.

Step four: Oxidation:
               The hydroxyl group (alcohol) is oxidized to carbonyl (ketonic group) using oxidizing agent Chromic acid (H</span>₂CrO₄).

8 0
3 years ago
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