Can someone help with thsi? i will give brainliest
1 answer:
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Answer:
B. Ball B will take longer to complete one cycle
Explanation:
This is simply because the period of a simple pendulum is affected by acceleration due to gravity, while the period of an ideal spring is not.
This can be clearly deduced by observing the formulas for the various systems.
Formula for period of simple pendulum:
T = 2π ×
Formula for period of an oscillating spring:
T= 2π ×
The period of the simple pendulum is affected by the length of the string and the acceleration due to gravity as shown above. Thus, it will have a different period as the gravitational acceleration changes on the moon. Thus will be a larger period <em>(slower oscillation) </em>as the gravitational acceleration is smaller in this case
The period of the oscillating spring is only affected by the mass of the load an the spring constant as shown above. Thus, it will have a period similar to the one it had on the earth because the mass of the ball did not change as the setup was taken to the moon.
All these will make the ball on the spring (Ball B) oscillate faster than the ball swinging on the string (Ball A)