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son4ous [18]
3 years ago
14

Given: g = 9.8 m/s 2 . A small glass of water is placed on carousel inside a microwave oven, at a radius 6.5 cm from the center.

The carousel rotates steadily, tuning through one revolution every 9.3 s. What angle does the water surface make with the horizontal? Answer in units of ◦ .
Physics
1 answer:
pashok25 [27]3 years ago
7 0

Answer:

0.17 degrees

Explanation:

From the question we are given the following:

acceleration due to gravity = 9.8 \frac{m}{s^{2} }

radius (r) = 6.5 cm = 0.065 m

time (s) = 9.3 s

angle = ?

  • we first have to calculate the distance the water moves, and this is the circumference of the microwave

         circumference = 2 x π x r = 2 x π x 0.065 = 0.408 m

  • Now we find the speed with which it moves at

            speed = \frac{distance}{time}

                         =  \frac{o.408}{9.3} = 0.044

  • The next step is to find the centripetal acceleration

         a = \frac{v^{2} }{r}

              = \frac{0.044^{2} }{0.065} = 0.03

being a vector quantity, acceleration has direction, the centripetal acceleration is the x component while the y component would be the acceleration due to gravity (g)

A = 0.03 x + 9.8 y

to find the angle we can apply tan θ = \frac{ 0.03 }{9.8

     θ  = 0.17 degrees

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3 0
4 years ago
If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen
amm1812

Answer:

y = 33.93 10⁵ m

Explanation:

This is an interference exercise, for the contributory interference is described by the expression

           d sin θ = m λ

let's use trigonometry for the angle

           tan θ = y / L

how the angles are small

          tan θ = sin θ / cos tea = sin θ

 

we substitute

         sin θ = y / L

        d y / L = m λ

         y = m λ L / d

the light fulfills the relation of the waves

       c = λ f

       λ = c / f

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let's calculate

        y = 1  8 10⁵  4030 10-9 / 950 10-9

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6 0
3 years ago
An object is moving to the west at a constant speed. three forces are exerted on the object. one force is 10 n directed due nort
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- force F1 with direction north, of 10 N
- force F2 with direction west, of 10 N
The third force must balance them, in order to have a net force of zero on the object.

The resultant of the two forces F1 and F2 is
F_{12} =  \sqrt{F_1^2+F_2^2}= \sqrt{(10 N)^2+(10 N)^2}= \sqrt{200}=14.1 N
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6 0
4 years ago
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