Determine which material is most likely to be a good conductor.

Identify the conjugate acid/base pairs in each of the following equations:

Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

Pair 2: NH₃ and NH₄⁺

(b) Pair 1: HSO₄⁻ and SO₄⁻

Pair 2: NH₃ and NH₄⁺

(c) Pair 1: HBr and Br⁻

Pair 2: CH₃O⁻ and CH₃OH

(d) Pair 1: HNO₃ and NO₃⁻

Pair 2: H₃O⁺

Explanation:

When an acid loses its proton (H⁺), a conjugate base is produced.

When a base accepts a proton (H⁺), it forms a conjugate acid.

(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻.

NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺

(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.

The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.

(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.

CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH.

(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

H₂O gains a proton to form the conjugate acid H₃O⁺.

6 0

3 years ago

THIS IS A THREE PART QUESTION IF YOU CAN HELP IT WOULD BE REALLY APPRECIATED SO I DONT FAIL.

Nostrana [21]

Answer:

1. B = 1.13M

2. A. 8.46%

3. D = 0.0199

Explanation:

1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

Molarity of solution = 2.988 mols/ 2.65 L = 1.13 M

2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

Mass of 2.65 L of water = density × volume

Density of water = 1 Kg/L = 1000 g/L; volume of waterb= 2.65 L

Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

Moles of water = mass /molar mass

Mass of water = 2650 g; molar mass of water = 18 g/mol

Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

6 0

4 years ago

Each of the following values was read on an instrument of measuring device. In each case the last digit was estimated. Tell what

Drupady [299]

Answer:

Explanation:

6 0

3 years ago

An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the

maxonik [38]

Answer:

Molarity of $KIO_{3}$ solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of $KIO_{3}$ = 214 g/mol

So, 562 g of $KIO_{3}$ = $\frac{562}{214}$ moles of $KIO_{3}$ = 2.63 moles of $KIO_{3}$

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is $KIO_{3}$ and solvent is water

Total volume of solution is 4.30 L

So, molarity of $KIO_{3}$ solution = $\frac{2.63}{4.30}mol/L$ = 0.612 mol/L

3 0

3 years ago

Am i correct...........................................

Kitty [74]

yes it is correct the ring of fire was located in the pacific ocean

4 0

4 years ago

Read 2 more answers