Acid = donor (giver) proton (H + ion)
Base = acceptor (receiver) proton (H + ion)
<h3><em>Further explanation</em></h3>Based on Bronsted-Lowry Theory, acid is an ion/molecule that acts as a proton donor (H +) to other ions/molecules. While bases are ions/molecules that act as proton acceptors (H +).
If an acid gives its proton (H +), then the rest of the acid can accept the proton and function as the conjugate base of the acid
Conversely, if a base is a proton acceptor (H +), then the ion/molecule formed can release the proton and function as a conjugate acid from that base. In general, these conjugate acid-base pairs can be described as follows:
Example
NH₃ (aq) + H₂O (l) ------> NH₄ + (aq) + OH– (aq)
Basa Asam Asam Basa
The acid-base conjugate pair is:
NH₃ and NH₄
H₂O and OH-
H₂O as an acid gives a proton to NH₃ so that it becomes NH₄ so that the remaining OH- as its conjugate base
While NH₃ as a base and NH₄ as a conjugate acid
Example 2:
HOCN + H₂O ------> H₃O⁺ + OCN⁻
The conjugate base of HOCN is OCN⁻ because OCN⁻ is the proton acceptor of H⁺ to form HOCN (as an acid)
<h3><em>Learn more</em></h3>the Bronsted-Lowry definition of an acid
the Bronsted-Lowry definition of a base
the acids and the bases in the chemical equation according to Bronsted-Lowry Theory
Keywords: Bronsted-Lowry Theory, acid, base, proton, donor, acceptor, acid-base conjugate
Answer:
About 0.0940 M.
Explanation:
Recall that NaOH is a strong base, so it dissociates completely into Na⁺ and OH⁻ ions. Because the acid is monoprotic, we can represent it with HA. Thus, the reaction between HA and NaOH is:
Using the fact that it took 15.00 mL of NaOH to reach the endpoint, determine the number of HA that was reacted with:
Therefore, the molarity of the original solution was:
In conclusion, the molarity of the unknown acid is about 0.0940 M.