Acid = donor (giver) proton (H + ion)
Base = acceptor (receiver) proton (H + ion)
<h3><em>Further explanation</em></h3>Based on Bronsted-Lowry Theory, acid is an ion/molecule that acts as a proton donor (H +) to other ions/molecules. While bases are ions/molecules that act as proton acceptors (H +).
If an acid gives its proton (H +), then the rest of the acid can accept the proton and function as the conjugate base of the acid
Conversely, if a base is a proton acceptor (H +), then the ion/molecule formed can release the proton and function as a conjugate acid from that base. In general, these conjugate acid-base pairs can be described as follows:
Example
NH₃ (aq) + H₂O (l) ------> NH₄ + (aq) + OH– (aq)
Basa Asam Asam Basa
The acid-base conjugate pair is:
NH₃ and NH₄
H₂O and OH-
H₂O as an acid gives a proton to NH₃ so that it becomes NH₄ so that the remaining OH- as its conjugate base
While NH₃ as a base and NH₄ as a conjugate acid
Example 2:
HOCN + H₂O ------> H₃O⁺ + OCN⁻
The conjugate base of HOCN is OCN⁻ because OCN⁻ is the proton acceptor of H⁺ to form HOCN (as an acid)
<h3><em>Learn more</em></h3>the Bronsted-Lowry definition of an acid
the Bronsted-Lowry definition of a base
the acids and the bases in the chemical equation according to Bronsted-Lowry Theory
Keywords: Bronsted-Lowry Theory, acid, base, proton, donor, acceptor, acid-base conjugate
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,
Compound's mass,
= 0.4647 g
Let the compound's formula will be:
Combustion's general equation will be:
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
Now,
x : y : z =
=
=
=
So that the empirical formula seems to be "C₃H₆O₂".