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alina1380 [7]
4 years ago
10

How do you know which planet is farther away from the sun by years?

Chemistry
1 answer:
vladimir1956 [14]4 years ago
4 0

I believe the answer is B

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The density of table salt is 2.16 g/cm3. Detail the conversion into units of pounds per liter, and provide the density in lb/L.
Leona [35]

Answer:

density = 4.763pounds per liter

Explanation:

1g/cm³ = 2.205pounds per liter

2.16g/cm³ = (unknown)pounds per liter

(unknown)pounds per liter = 2.205 x 2.16 = 4.763

density = 4.763pounds per liter

4 0
3 years ago
What results when two waves that are completely out of phase meet?
ELEN [110]

Answer:

The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.

Explanation:

The result is a superposition which is twice the amplitude of each input wave. Φ = π means the two waves are completely OUT OF PHASE, and so add completely destructively. The result is a superposition which has no amplitude at all.

5 0
2 years ago
Read 2 more answers
An elastic cord can be stretched to its elastic limit by a load of 2N.If a 35cm length of the cord is extended 0.6cm by a force
Levart [38]

Explanation:

from \: hookes \: law \\ F = k.e \\ but \: e = 0.6 \: cm \\ 2 = k \times 0.6 \\ k = 3.33 \\ when \:F \: is \: 2.5 \\ 2.5 = 3.33 \times e {}^{.}   \\  {e}^{. }  = 0.75 \: cm \\ new \: length = 35 -  {e}^{.}  \\  = 35 - 0.75 \\  = 34.25 \: cm

3 0
3 years ago
The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric)
valkas [14]

The production of CO_{2} is 3.3480\times 10^{4} tons/day. Converting mass into kg,

1 ton=907.185 kg, thus,

3.3480\times 10^{4} tons=3.037\times 10^{7} kg

Thus, production of CO_{2} will be 3.037\times 10^{7} kg/ day.

The specific volume of CO_{2} is 0.0120 m^{3}/kg.

Volume of CO_{2} produced per day can be calculated as:

V=Specific volume\times mass

Putting the values,

V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day

Thus, volume of CO_{2} produced per year will be:

V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year

Thus, in 4 year volume of CO_{2} produced will be:

V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}

8 0
3 years ago
8. If a chemical reaction such as photosynthesis begins with 6 atoms of carbon (C), how many atoms of carbon (C) should be in th
NISA [10]

Answer

b

Explanation:

4 0
3 years ago
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