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4 years ago

Question 24

1 answer:

8 0

Q 24: Newton's first law of motion states that anything that stands still will stay still unless unbalanced force is acted upon that object. Newton's second law of motion states that the velocity of an object changes when subjected to external Force. Newton's third law of motion says that for every action there is an equal and opposite reaction. when bumper cars crash into each other one car goes one way and the other goes the other way.

Q 25: if the bumper cars doubled their Mass the motion would be halfed but if the net force is doubled the motion will double.

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Terms used to measure motion

pychu [463]

Answer:

velocity term

Explanation:

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3 years ago

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PLEASE HELP

bixtya [17]

Answer:

AS- X 3.42 Y 3. B) X Y c) x Ross TET V V. a 1.71 1.71 LLL LLL 2.42 N al

Explanation:

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3 years ago

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Compute the order of magnitude of the mass of a bathtub half full of pennies. (Assume the pennies are made entirely of copper.)

devlian [24]

Answer:

Mass = 873.6kg = 0.874 × 10^3 kg

Order = 3

Question:

Compute the order of magnitude of the mass of a bathtub half full of pennies.(Assume the pennies are made entirely of copper and the tub measures 1.3 m by 0.5 m by 0.3 m)

Explanation:

Given:

Dimensions of the tub = 1.3 m by 0.5 m by 0.3 m

Density of copper d = 8960kg/m^3

Mass = volume × density

Volume of tub = L×B×H = 1.3 × 0.5 × 0.3 = 0.195m^3

Since the tub is half full:

V = 0.195/2 = 0.0975m^3

Mass = 8960kg/m^3 × 0.0975m^3

Mass = 873.6kg = 0.874 × 10^3 kg

Order = 3

Note: Order of magnitude is of the form:

N = a × 10^b

Where;

b = order of magnitude

and

1/√10 </= a < √10

8 0

4 years ago

You need to design a 60.0-Hz ac generator that has a maximum emf of 5200 V. The generator is to contain a 180-turn coil that has

OlgaM077 [116]

Answer:

0.082 T

Explanation:

Given:

Frequency of the generator (f) = 60.0 Hz

Maximum emf of the generator (E) = 5200 V

Number of turns (N) = 180

Area per turn (A) = 0.94 m²

Magnetic field magnitude (B) = ?

We know that, the angular frequency of the generator is given as:

$\omega=2\pi f$

Plug in the value of 'f' and solve for 'ω'. This gives,

$\omega=2\pi\times 60.0=120\pi\ rad/s$

Now, the maximum emf of the generator is given by the formula:

$E=NAB\omega$

Rewriting in terms of magnetic field, 'B', we get:

$B=\frac{E}{NA \omega}$

Plug in the given values and solve for 'B'. This gives,

$B=\frac{5200\ V}{180\times 0.94\ m^2\times 120\pi\ rad/s}\\\\B=\frac{5200\ V}{63786.897}\\\\B=0.082\ T$

Therefore, the magnitude of the magnetic field in which the coil rotates is 0.082 T.

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4 years ago

A measure of how much pulling, or tension, a material can withstand before breaking is -

andre [41]

It should be C......................

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4 years ago

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