Answer:
mg = 30.415 lbf
Explanation:
from figure body of size 3ft*2ft is tend to move down side
weight is divided into two component
vertical component = mgcos15 and
horizontal component = mg sin15
considering horizontal component equal to shear force
mgsin15 = \tau A
mgsin15 =\mu \frac{dv}{dh} A
mg =\frac{ \mu v A}{h*sin15}
=\frac{8.2*10^{-2}*0.2*3*2}{0.0125*sin15}
mg = 30.415 lbf
Answer: Covalent bond
Explanation: Covalent bond is the bond that gets created when there is a sharing of electrons among atoms and hence creating atomic interaction. The bond formed is from the shared pair because they allow the atoms or ions to achieve stability by completely filling the outer shell of the electron and thus form the covalent bond .Therefore, the correct option is the option(b) .
Answer:
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Answer:
<em>minimum required diameter of the steel linkage is 3.57 mm</em>
<em></em>
Explanation:
original length of linkage l = 10 m
force to be transmitted f = 2 kN = 2000 N
extension e = 5 mm= 0.005 m
maximum stress σ = 200 N/mm^2 = 
maximum stress allowed on material σ = force/area
imputing values,
200 = 2000/area
area = 2000/(
) =
m^2
recall that area = 
=
= 
= 
=
m = 3.57 mm
<em>maximum diameter of the steel linkage d = 3.57 mm</em>
Answer:
- F1.x ≈ -28.93
- F1.y ≈ 34.47
- F2.x = 70
- F2.y = 0
- (F1+F2).x ≈ 41.07
- (F1+F2).y ≈ 34.47
- |F1+F2| ≈ 53.62
- ∠(F1+F2) ≈ 40.0°
Explanation:
A suitable calculator can show you the vector components and their resultant in polar or rectangular format. (See attached.) 2D vectors are conveniently treated as complex numbers, which is why the y-component values are shown as imaginary.
(The 50° angle measured from the -x axis is equivalent to 130° measured from the +x axis, which is the reference we're using here.)
If you'd like to compute the vector components by hand, they are ...
(x, y) = magnitude×(cos(angle), sin(angle))
This notation is sometimes abbreviated <em>magnitude cis angle</em>, a reference to the complex number form x+yi.