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3 years ago

The voltage across a device and the current through it are:

Engineering

2 answers:

Strike441 [17]3 years ago

7 0

Answer: Charge, Q= 22.131 columbs

Power, P = 196.65 Watts

Explanation:

I(t) = 10( 1 - e(-0.5t)) A

I = dQ/dt

dQ = 10( 1 - e(-0.5t))dt

Integrating we have

Q = 10t - (20/(-0.5))e(-0.5t)

taking the value of t at 1s

we have,

Q = 10 + 20e(-0.5)

Q = 10 + 20/1.6487

Q = 10 + 12.131

Q = 22.131 Columbs

(b) Power

Power = voltage x current

Power = 5cos(2t) x 10(1 - e(-0.5t))

Power at t= 1, we substitute t=1

Power = 5cos(2) x 10(1 - e(-0.5))

Power = 5(0.9995) x 10(1 - 0.60654)

Power = 39.35 x 4.9975 = 196.65 Watts

Power = 196.65 Watts

butalik [34]3 years ago

3 0

Answer:

attached below

Explanation:

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Question Continuation

int factorial(int n) {

if(n == 0)

return 1;

else

return n * factorial(n - 1);

}

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Answer:

1. Brief explanation why this recursive function works.

First, the recursive method factorial is defined.

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2. Steps to calculate factorial(3)

1 First, 3 is assigned to n.

2. At line 2, the machine checks if n equals 0

3. If yes, the machine prints 1

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factorial(3):

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3 years ago

An insulated rigid tank is initially evacuated. A valve is opened, and atmospheric air at 95 kPa and 17 ºC enters the tank until

Darya [45]

Answer:

$T2= 406k$

Explanation:

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T1=170C

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= 17+273 =290K

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