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Savatey [412]
4 years ago
6

a sample of a substance has a mass of 52.5g and displaces a volume of 4.2ml. what is the density of the substance

Chemistry
1 answer:
Lena [83]4 years ago
3 0

Answer:

<h2>Density = 12.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 52.5 g

volume = 4.2 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{52.5}{4.2}  \\

We have the final answer as

<h3>Density = 12.5 g/mL</h3>

Hope this helps you

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Propose a structure for an aromatic hydrocarbon, C9H12, that can form two C9H11Cl products on substitution of a hydrogen on the
Crank

Answer:

Explanation:

From the given study,

the molecular formula of the given aromatic compound = C9H12

the first process we suppose to carry out is to calculate the double bond equivalence.

So, the double bond equivalence DBE = {N_C+1-(\dfrac{(N_H+N_{Cl})-N_H}{2})  }

DBE = {9+1-(\dfrac{(12+0)-0}{2})  }

DBE = 4

Hence, the aromatic compound possesses 4 double bonds, this signifies that the might be a presence of benzene ring.

The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.

3 0
3 years ago
Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
3 years ago
WILL MARK BRAINLIEST WORTH 20 POINTS PLEASE HELP ASAP
s2008m [1.1K]

Answer:

A

Explanation:

Hydrogen and chlorine need to be balanced. There is an equal amount of magnesium on each side

3 0
3 years ago
HELP MEEEE ASAP!!! Answer these questions based on what you learned from the passage. You can assume any body structure comes fr
erica [24]

Answer:

1.Legs

2.Arms and hands

3.Armor

4.Skeletal

5.Carpenters

6.Brain

7.Skin

8.Blood

Explanation:

You can google dem and it will show you all the answers

4 0
4 years ago
A compound was decomposed and determined to be 51.27 % C, 7.75 % H and 40.98 % O by mass. What is the subscript for H in the emp
Vlad [161]

The subscript for H in the empirical formula for this compound is 3.

There are 3 steps involved in the construction of empirical formula.

Calculation of empirical formula is as under as ...

Step 1: Divide the % of each atoms which their atomic weights.

 C = 51.27 / 12 = 4.27

 H = 7.75 / 1 = 7.75

 O = 40.98 / 16 =2.56

Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.

C = 4.27/ 2.56 ≈ 2

H = 7.75/ 2.56 ≈ 3

O = 2.56 /2.56 = 1

Step 3: Construction of empirical formula by putting subscripts calculated in step 2.

Empirical formula form given data = C_{2} H_{3} O_{1}

Thus , subscript for H in the empirical formula for this compound is 3.

Learn more about empirical formula here..

brainly.com/question/13058832

#SPJ4

4 0
2 years ago
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