A substance is followed by the symbol (1) in a chemical equation. What does the symbol represent?

Chemistry

1 answer:

alekssr [168]2 years ago

5 0

Answer:

The symbol (l) stands for liquid phase.

Explanation:

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Materials

nikitadnepr [17]

Answer:

Limestone caves are formed when acid rain occurs.

Explanation:

When chalk pieces which is made of calcium carbonate react with acetic acid, it produces carbon dioxide, calcium acetate, and water. When calcium carbonate react with Carbonated Water produces calcium bicarbonate. Limestone cave forms when the dissolution of limestone occur when rainwater which is acidic due to the addition of carbondioxide in the air react with limestone. This dissolution removes the lime from the rock and caves are formed.

8 0

3 years ago

What is the mass in milligrams of 4.30 moles of sodium?use âeâ for âÃ10" and use significant figures?

Elis [28]

First, calculate the mass of sodium in g with the help of molar mass and number of moles.

Number of moles = $\frac{given mass in g}{molar mass}$ (1)

Molar mass of sodium = $23 .0 g/mol$

Substitute the given value of number of moles and molar mass of sodium in formula (1)

$4.30 moles = \frac{given mass in g}{23.0 g/mol}$ (1)

$4.30 moles\times 23.0 g/mol = mass in g$ (1)

mass of sodium in g = $98.9 g$

Now, according to conversion factor, 1 g = 1000 mg

So, $98.9 g$ of sodium = $98.9 \times 1000 mg$

= $98900 mg$ of sodium

Thus, mass of sodium in mg = $9.89 \times 10^{4} mg$

8 0

3 years ago

The whiye pigment TiO2 is prepared by the reaction of titanium tetrachloride, TiCl4, with water vapor in the gas phase:

omeli [17]

Answer:

$\boxed{\text{62.1 kJ}}$

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

TiCl₄(g) + 2H₂O(g) ⟶ TiO₂(s) + 4HCl(g)

ΔH°f/kJ·mol⁻¹: -763.2 -241.828 -939.7 -92.307

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-939.7 + 4(-92.307)] - [-763.2 + 2(-241.828)\\& = & [-939.7 - 369.228] - [-763.2 - 483.656]\\& = & -1308.928 + 1246.856\\& = & \mathbf{-62.1}\\\end{array}\\\text{The amount of heat evolved is } \boxed{\textbf{62.1 kJ}}$