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hram777 [196]
3 years ago
10

1. The area(in square centimeters) of a square coaster can be represented by

Engineering
1 answer:
Brrunno [24]3 years ago
7 0

Answer: (d−4) 2

Explanation: Factoring  d2-8d+16

The first term is,  d2  its coefficient is  1 .

The middle term is,  -8d  its coefficient is  -8 .

The last term, "the constant", is  +16

Step-1 : Multiply the coefficient of the first term by the constant   1 • 16 = 16

Step-2 : Find two factors of  16  whose sum equals the coefficient of the middle term, which is   -8 .

     -16    +    -1    =    -17

     -8    +    -2    =    -10

     -4    +    -4    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  -4

                    d2 - 4d - 4d - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

                   d • (d-4)

             Add up the last 2 terms, pulling out common factors :

                   4 • (d-4)

Step-5 : Add up the four terms of step 4 :

                   (d-4)  •  (d-4)

            Which is the desired factorization

  Multiply  (d-4)  by  (d-4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (d-4)  and the exponents are :

         1 , as  (d-4)  is the same number as  (d-4)1

and   1 , as  (d-4)  is the same number as  (d-4)1

The product is therefore,  (d-4)(1+1) = (d-4)2

Please mark me brainlyest

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To solve this problem it is necessary to apply the concepts related to the heat exchange of a body.

By definition heat exchange in terms of mass flow can be expressed as

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Where

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Our values are given as

C_p = 1.005kJ/kgK \rightarrow Specific heat of air

T_1 = 50\°C

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From our equation we have that

W = \dot{m}c_p \Delta T

W = \dot{m}c_p (T_2-T_1)

Rearrange to find T_2

T_2 = \frac{W}{\dot{m}c_p}+T_1

Replacing

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A 200-gr (7000 gr = 1 lb) bullet goes from rest to 3300 ft/s in 0.0011 s. Determine the magnitude of the impulse imparted to the
OlgaM077 [116]

Answer:

The force acting on the bullet F = 84000 \frac{lb ft}{s^{2} }

The value of impulse on the bullet in the given time interval P = 92.4 \frac{lb ft}{sec}

Explanation:

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Final Velocity ( V ) = 3300 \frac{ft}{sec}

Force acting on the bullet F = \frac{m ( V - U )}{t}

⇒ F = \frac{ 0.028 ( 3300 - 0 )}{0.0011}

⇒ F = 84000 \frac{lb ft}{s^{2} }

This is the force acting on the bullet.

Magnitude of the impulse imparted on the bullet  P = F dt  -------- (1)

Put the value of F & dt in above equation we get,

P = 84000 × 0.0011

P = 92.4 \frac{lb ft}{sec}

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A pressure gage at the inlet to a gas compressor indicates that the gage pressure is 40.0 kPa. Atmospheric pressure is 1.01 bar.
bonufazy [111]

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Given

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1. the absolute pressure of the gas at the inlet, inlet Pab?

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the absolute pressure of the gas at the inlet, inlet Pab = 141kpa

2. the gage pressure of the gas at the exit? exit Pga?

exit Pab = Patm + exit Pga

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              = 815.5kpa

the gage pressure of the gas at the exit exit Pga=815.5kpa

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