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Law Incorporation [45]
3 years ago
11

A company that produces footballs uses a proprietary mixture of ideal gases to inflate their footballs. If the temperature of 23

0 grams [g] of gas mixture in a 15-liter [L] tank is maintained at 465 degrees Rankine [°R] and the tank is pressurized to 135 pound-force per square inch [psi], what is the molecular weight of the gas mixture in units of grams per mole [g/mol]?
Engineering
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

35 g/mol

Explanation:

Convert to SI units.

465 R × 5/9 = 258.3 K

Assuming the pressure is absolute pressure:

135 psi × (101.3 kPa / 14.7 psi) = 930.3 kPa

Ideal gas law:

PV = nRT

(930.3 kPa) (15 L) = n (8.314 kPa L / mol / K) (258.3 K)

n = 6.50 mol

The molar mass is therefore:

230 g / 6.50 mol = 35.4 g/mol

Rounded to two significant figures, the molar mass is 35 g/mol.

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I WILL GIVE 20 POINTS!!
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Answer:

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Resolver em c as equações:<br><br> Z elevado à 2 igual a 3+4i
Marrrta [24]

Answer:

Quando um (ou todos) os outros coeficientes de uma equação do segundo grau são iguais a zero, essa equação é chamada incompleta. Neste artigo, analisaremos os métodos que podem ser usados para resolver equações incompletas, no caso em que o coeficiente C = 0, ou seja, o coeficiente é nulo.

Explanation:

Um lado da equação será a potência e outro, o número inteiro. De outro modo, transforme a equação deixando-a isolada em um dos lados. Reescreva a equação. Prepare-a a fim de extrair o logaritmo de ambos os lados, que é o inverso da potência. Você pode calcular o logaritmo de base.

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A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is
patriot [66]

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)=20 W/m^2-K

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Write a SELECT statement that returns the same result set as this SELECT statement, but don’t use a join. Instead, use a subquer
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Answer:

See explanation

Explanation:

The complete question is

Write a SELECT statement that returns the same result set as this SELECT statement, but don't use a

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SELECT DISTINCT category_name

FROM categories c JOIN products p

ON c.category_id = p.category_id

ORDER BY category_name

The join clause  gives us all the registers of both tables, for which the category_id of categories coincides to  the category_id in the table products. That is, we can first select the distinct category_id's from products and the see the categories from categories table, whose id is in that list. That means writing the following query:

Select distinct category_name

from categories c

where c.category_id in (

select distinct p.category_id

from products p)

order by category_name

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4 years ago
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