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NemiM [27]
4 years ago
6

Sound wave A delivers 2J of energy in 2s. Sound wave length B delivers 10J of energy in 5s. Sound wave C delivers 2mJ of energy

in 1ms. Rank in order, from largest to smallest, the sound powers of Pa, Pb, Pc of these three waves.Explain. What equation would you use to determine this?
Physics
1 answer:
Norma-Jean [14]4 years ago
7 0

Answer:

P_c=P_b>P_a

Explanation:

E = Energy

T = Time

Power is given by the equation

P=\frac{E}{T}

For first case

P_a=\frac{2}{2}\\\Rightarrow P_a=1\ W

For second case

P_b=\frac{10}{5}\\\Rightarrow P_b=2\ J

For third case

P_c=\frac{2\times 10^{-3}}{1\times 10^{-3}}\\\Rightarrow P_b=2\ J

The rank of power would be P_c=P_b>P_a

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What happens to the pressure of a gas inside a container if the temperature of the gas decreases?
My name is Ann [436]

Answer:

Pressure Increases

Explanation:

When the temperature of a gas is increased inside a container then the pressure of the gas inside the container increases.

This can be deduced by the Ideal Gas law equation:

P.V=n.R.T

where:

P = pressure of the gas

V = volume of the gas

n = no. of moles of gas

R = universal gas constant

T= temperature of the gas

So,

P\propto T hence the pressure of the gas will increase while the temperature is increased at a constant volume

5 0
3 years ago
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In which type of wave do air particles move together or apart parallel to the direction of the wave?
Phoenix [80]
The best and most correct answer among the choices provided by the question is <span>B.sound waves</span><span>.
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<span>Particles move together or apart parallel to the direction of the sound wave.
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Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.
8 0
4 years ago
Please answer this question
nata0808 [166]

Answer:

Its sure 2nd gare beaciuse

Explanation:

of tobi was obito was tobi his som came and start doing enginner but he faild so i gave him answer he repiled oh baby baby oh

5 0
3 years ago
As important as it is to plan ahead,sometimes you
Natali5045456 [20]

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B. Cant stop things from going wrong.

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Suppose a small planet is discovered that is 16 times as far from the Sun as the Earth's distance is from the Sun. Use Kepler's
mamaluj [8]

Answer:

23376 days

Explanation:

The problem can be solved using Kepler's third law of planetary motion which states that the square of the period T of a planet round the sun is directly proportional to the cube of its mean distance R from the sun.

T^2\alpha R^3\\T^2=kR^3.......................(1)

where k is a constant.

From equation (1) we can deduce that the ratio of the square of the period of a planet to the cube of its mean distance from the sun is a constant.

\frac{T^2}{R^3}=k.......................(2)

Let the orbital period of the earth be T_e and its mean distance of from the sun be R_e.

Also let the orbital period of the planet be T_p and its mean distance from the sun be R_p.

Equation (2) therefore implies the following;

\frac{T_e^2}{R_e^3}=\frac{T_p^2}{R_p^3}....................(3)

We make the period of the planet T_p the subject of formula as follows;

T_p^2=\frac{T_e^2R_p^3}{R_e^3}\\T_p=\sqrt{\frac{T_e^2R_p^3}{R_e^3}\\}................(4)

But recall that from the problem stated, the mean distance of the planet from the sun is 16 times that of the earth, so therefore

R_p=16R_e...............(5)

Substituting equation (5) into (4), we obtain the following;

T_p=\sqrt{\frac{T_e^2(16R_e)^3}{(R_e^3}\\}\\T_p=\sqrt{\frac{T_e^24096R_e^3}{R_e^3}\\}

R_e^3 cancels out and we are left with the following;

T_p=\sqrt{4096T_e^2}\\T_p=64T_e..............(6)

Recall that the orbital period of the earth is about 365.25 days, hence;

T_p=64*365.25\\T_p=23376days

4 0
3 years ago
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