(a) The velocity (in m/s) of the rock after 1 second is 11.28 m/s.
(b) The velocity of the rock after 2 seconds is 7.56 m/s.
(c) The time for the block to hit the surface is 4.03.
(d) The velocity of the block at the maximum height is 0.
<h3>
Velocity of the rock</h3>
The velocity of the rock is determined as shown below;
Height of the rock after 1 second; H(t) = 15(1) - 1.86(1)² = 13.14 m
v² = u² - 2gh
where;
- g is acceleration due to gravity in mars = 3.72 m/s²
v² = (15)² - 2(3.72)(13.14)
v² = 127.23
v = √127.23
v = 11.28 m/s
<h3>Velocity of the rock when t = 2 second</h3>
v = dh/dt
v = 15 - 3.72t
v(2) = 15 - 3.72(2)
v(2) = 7.56 m/s
<h3>Time for the rock to reach maximum height</h3>
dh/dt = 0
15 - 3.72t = 0
t = 4.03 s
<h3>Velocity of the rock when it hits the surface</h3>
v = u - gt
v = 15 - 3.72(4.03)
v = 0
Learn more about velocity at maximum height here: brainly.com/question/14638187
Because a sxientific law is always applies under the same conditions, and implies that there is a causal relationship involving its elements. And so that is why gravity <span>always applies under the same conditions, and implies that there is a causal relationship involving its elements.</span>
42- C
43- A
44- C
45- A
46- B
47- D
Answer:
75 N
Explanation:
In this problem, the position of the crate at time t is given by
The velocity of the crate vs time is given by the derivative of the position, so it is:
Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:
[m/s^2]
According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:
where
m = 5.00 kg is the mass of the crate
At t = 4.10 s, the acceleration of the crate is
And therefore, the force on the crate is:
Answer:
the answer is 3600 kilometers
