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NemiM [27]
4 years ago
6

Sound wave A delivers 2J of energy in 2s. Sound wave length B delivers 10J of energy in 5s. Sound wave C delivers 2mJ of energy

in 1ms. Rank in order, from largest to smallest, the sound powers of Pa, Pb, Pc of these three waves.Explain. What equation would you use to determine this?
Physics
1 answer:
Norma-Jean [14]4 years ago
7 0

Answer:

P_c=P_b>P_a

Explanation:

E = Energy

T = Time

Power is given by the equation

P=\frac{E}{T}

For first case

P_a=\frac{2}{2}\\\Rightarrow P_a=1\ W

For second case

P_b=\frac{10}{5}\\\Rightarrow P_b=2\ J

For third case

P_c=\frac{2\times 10^{-3}}{1\times 10^{-3}}\\\Rightarrow P_b=2\ J

The rank of power would be P_c=P_b>P_a

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A rubber band has a spring constant of 15 N/m. If you stretch it by 0.3 m,
borishaifa [10]

Answer:

B. 4.5N

Explanation:

F = kx

Where

F = force

K = spring constant

x = compression

Given

K = 15N/m

x = 0.3m

Therefore

F = 15 x 0.3

F = 4.5N

The magnitude of the force that resists the stretching is 4.5N

5 0
4 years ago
While loading, a truck moves 10 meters west from point A to point B in 5 seconds. Then it moves back to point A in 5 seconds. Wh
Talja [164]

Answer:

2m/s

Explanation:

distance(s)=10m

time taken(t)=5s

Now,

Speed(s)=s/t

=10m/5s

=2m/s [•.• 10/5=2]

5 0
3 years ago
Help!!! This is worth 30 points pls pls pls help help help
Ksivusya [100]

Answer:

The tennis ball is moving 6m/s.

Explanation:

displacement(s) = 0.5 m

intial velocity(u) = 4 m/s

acceleration(a) = 10 m/s²

As we know,

2as = v²-u²

or, 2 ×10 × 0.5 = v²-4²

or, 10 = v²-16

so, v² = 36

so, v (final velocity) = 6 m/s

8 0
3 years ago
Read 2 more answers
A rubber ball is dropped from a height of 8m. After strikingthe floor, the ball bounces to a height of 5m. a. If the ball had bo
kifflom [539]

Answer:

a) This means the collision between the ball and the floor is elastic.

b) This points to a perfectly inelastic collision between the ball and the floor as they stick together after collision

c) Check Explanation.

Explanation:

Collision of bodies are analysed according to whether both momentum and kinetic energy of the system is conserved, that is, if these two quantities before collision are equal to their values after collision.

In all types of collisions, momentum is usually conserved, but kinetic energy is conserved only in an elastic collision.

A ball dropped from a height of 8 m bounces up back to a height of 5 m.

a. If the ball had bounced to a height of 8m, how would you describe the collision between the ball and the floor?

The ball not bouncing back to a height of 8 m shows energy loss at some point in the total motion of the ball (most likely at the collision). If kinetic energy was conserved, the ball would bounce back up to the height at which it fell from (8 m) after the collision with the floor.

b. If the ball had not bounced at all, how would you describe the collision between the ball and the floor?

If the ball had not bounced at all, this means it lost all of its kinetic energy to the floor, and this points to a perfectly inelastic collision between the ball and the floor as they stick together after collision.

c. What happened to the energy lost by the ball during thecollision?

The energy lost during the collision is converted to another form, most likely responsible for some deformation on the ball & a minute deformation on the floor, converted to some form of heat as a result of the collision or into sound energy, usually, it's a combination of all This!

Hope this Helps!!!

5 0
4 years ago
Help please <br><br><br> -spaceholder this is-
4vir4ik [10]

Explanation:

I don't have time for you

4 0
4 years ago
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