At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.
<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
- At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
- However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
- u= initial velocity, θ= angle of projection
<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
- During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
- But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.
Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
A- neither the ball's velocity nor its acceleration are zero.
B- the ball's acceleration points upward.
C- the ball's acceleration is zero but its velocity is not zero.
D- the ball's velocity points downward.
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Answer:
The correct answer is "0.246".
Explanation:
Given that the amplitude is decreased by a factor of 9, then


As we know,
Energy will be:
⇒
and,
⇒ 

⇒ 
On putting the estimated values, we get

⇒ 


Explanation:
Given that,
Wavelength of the light, 
(a) Slit width, 
The angle that locates the first dark fringe is given by :



(b) Slit width, 
The angle that locates the first dark fringe is given by :



Hence, this is the required solution.
Answer:
The Total Mechanical Energy
As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
Explanation:
Answer:
75.84%
Explanation:
We were given Speed of the sports car, v as 80 mph , we can convert to m/s for unit consistency.
v=80mph= 35.76 m/s
The radius of curvature is given as , r = 540 m
✓ the normal weight can be denoted as Wn
✓ the apparent weight of the person can be denoted as Wa
Wn= normal weight= mg
Wa=apparent weight = (mg - mv^2/r)
g= acceleration due to gravity= 9.8m/s^2
The apparent weightand normal weight has a ratio of
Mn/Ma= [mg - mv^2/r]/mg ........eqn(1)
If we simplify eqn(1) we have
Mn/Ma=[g - vr^2/g].............eqn(2)
Then substitute the given values
Mn/Ma=9.8 - [(35.76^2)/540]/ 9.8
=0.758×100%
Mn/Ma=75.84%
Hence, the required fraction is 75.84%