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3 years ago

According to your textbook, the closest match for “nervous breakdown” would be

Physics

1 answer:

Dennis_Churaev [7]3 years ago

7 0

A "nervous breakdown" is usually caused by anxiety.

I hope this helps! -Wajiha

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Compared to the size and density of Earth, the Moon has a A. smaller diameter and lower density B. smaller diameter and higher d

MrRa [10]

Answer:

(a) Moon has smaller diameter and lower density than earth

Explanation:

Moon has smaller diameter than earth earth has a diameter of 12742 km whereas moon has a diameter of 3474.21 km

So for density density is given by $density=\frac{mass}{volume}$

From the relation we can see that density is dependent on mass and volume directly proportional to mass and inversely proportional to diameter

But in case of earth and moon mass is more dominating than volume so density is less for moon than earth

6 0

3 years ago

In the compound MgCl2, how many atoms of Mg are there?

Aleksandr [31]

There is 1 Mg and 2 Cl i think

3 0

3 years ago

A criminalist collects small strands of fabric from a crime scene. Which type of evidence is he detecting?

kozerog [31]

Trace evidence i beileve

4 0

3 years ago

Explain why is dressing table mirror may become dirsty if wiped with a cloth on a warm day.

gogolik [260]

<h2>Answer:</h2>

<em>When you rub a dry cloth across glass, it creates charged static electricity, which attracts little non-charged dust particles.</em>

6 0

3 years ago

Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e

antoniya [11.8K]

Answer:

$r=5.278\times 10^{-4}\ m$

Explanation:

Given that:

magnetic field intensity, $B=0.07\ T$

kinetic energy of electron, $KE=1.2\ eV= 1.2\times 1.6\times 10^{-19}\ J= 1.92\times 10^{-19}\ J$

we have mass of electron, $m=9.1\times 10^{-31}\ kg$

<em>Now, form the mathematical expression of Kinetic Energy:</em>

$KE= \frac{1}{2} m.v^2$

$1.92\times 10^{-19}=0.5\times 9.1\times 10^{-31}\times v^2$

$v^2=4.2198\times 10^{11}$

$v=6.496\times 10^6\ m.s^{-1}$

<u>from the relation of magnetic and centripetal forces we have the radius as:</u>

$r=\frac{m.v}{q.B}$

$r=\frac{9.1\times 10^{-31}\times 6.496\times 10^6 }{1.6\times 10^{-19}\times 0.07}$

$r=5.278\times 10^{-4}\ m$

6 0

4 years ago