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Digiron [165]
3 years ago
6

Plsss help I don’t understand this

Physics
2 answers:
nekit [7.7K]3 years ago
6 0

B is the correct option.

1. Given eqn;

S(t) = 1/2t² - 4t + 8

2.Differentiate the above eqn with respect to t;

<u>d(S(t))</u> = t - 4

dt

When distance, S, is differentiated it results to velocity.

V = t - 4

at t = 10

V = 10 - 4

V = 6 feet/s

mixer [17]3 years ago
4 0
The person above is correct, it’s B
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Answer:

230.4kg

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density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

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PHYSICS QUESTION, WILL MARK BRAINLIEST !!! A construction truck collides with the back of a subcompact car. Which one has the la
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8 0
3 years ago
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X-rays with an energy of 400 keV undergo Compton scattering with a target. If the scattered X-rays are detected at \theta = 30^{
marissa [1.9K]

Answer:

37.91594 keV

Explanation:

E_i = Incident energy = 400 keV

θ = 30°

h = Planck's constant = 4.135×10⁻¹⁵ eV s = 6.626×10⁻³⁴ J s

Incident photon wavelength

\lambda_i=\frac{hc}{E_i}\\\Rightarrow \lambda_i=\frac{4.135\times 10^{-15}\times 3\times 10^8}{400\times 10^3}\\\Rightarrow \lambda_i=3.101\times 10^{-12}\ m

Difference in wavelength

\Delta \lambda=\frac{h}{m_ec}(1-cos\theta)\\\Rightarrow \Delta \lambda=\frac{6.626\times 10^{-34}}{9.11\times 10^{-31}\times 3\times 10^8}(1-cos30)\\\Rightarrow \Delta \lambda=3.248\times 10^{-13}\ m

\lambda_f=\lambda_i+\Delta \lambda\\\Rightarrow \lambda_f=3.101\times 10^{-12}+3.248\times 10^{-13}\\\Rightarrow \lambda_f=3.426\times 10^{-12}

Final photon wavelength

\lambda_f=\frac{hc}{\lambda_f}\\\Rightarrow E_f=\frac{4.135\times 10^{-15}\times 3\times 10^8}{3.426\times 10^{-12}}\\\Rightarrow E_f=362084.06\ eV = 362.08406\ keV

Energy of the recoiling electron

\Delta E=E_i-E_f\\\Rightarrow \Delta E=400-362.08406=37.91594\ keV

Energy of the recoiling electron is 37.91594 keV

8 0
4 years ago
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