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4 years ago

What information can be learned about the element chlorine (Cl) by looking at the periodic table? Select all that apply.

Chemistry

2 answers:

olasank [31]4 years ago

5 0

That it is number 17 35.45 it's period is 3.

Hope that helped ^^

pantera1 [17]4 years ago

3 0

It's a halogen. It's a non metal. It's valency is 1. It is highly electronegative and non metallic in nature.

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What does the kinetic theory state about the relationship between the speed and temperature of gas molecules?

mario62 [17]

The kinetic theory state about the relationship between the speed and temperature of gas molecules "As the temperature increases, the speed of gas molecules increases".

Option: C

Explanation:

The temperature relates to a gas, according to the kinetic theory of gases, influences the rate of motion of the gas particles. The higher the gas temperature, the faster the gas particles are moving; the reverse is true, too.

This is because the gas particles gain more kinetic energy as the temperature of the gas increases, and therefore move faster and collide more with each other and the container walls.The rate of a gas's molecules is proportional to the temperature, and is inversely proportional to the gas's molar mass.

5 0

3 years ago

Write ground-state electron configurations for these ions, which play important roles in biochemical processes in our bodies. (U

Stella [2.4K]

1s s2 s4 s5 s6

Hope that helped

5 0

3 years ago

How many atoms of each element are in the following compound: C3H5(NO3)3

S_A_V [24]

Answer:

Hydrogen: 5

Carbon:3

Nitrogen:3

Oxygen: 9

please give me brainliest

6 0

2 years ago

When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr

poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

$E=-13.6*Z^{2}*(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} ) eV$

For the H transition n=5 to n=2:

$E=-13.6*(\frac{1}{4}-\frac{1}{25} ) eV=-2.856 eV$

Then we solve for nf with Z=2 (Helium)

$n_{f}=\sqrt{\frac{n_{i}^{2}*Z^{2}*13.6 eV }{2.856eV*n_{i}^{2}+13.6eV*Z^{2}} }$

$n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3$

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

4 0

3 years ago

A ray of yellow light has a wavelength of about 5.8×10−7 m. Will exposure to yellow light cause electrons to be emitted from ces

Igoryamba

The threshold frequency of Cesium is 5.2 x 10^14 Hz.

To find the frequency of yellow light, we use the equation:
speed of light = wavelength x frequency
3 x 10^8 = 5.8 x 10^-17 x frequency
frequency = 5.17 x 10^24

This is higher than the threshold frequency of Cesium, thus, electrons will be emitted.

7 0

4 years ago