Answer:
d
Explanation:
its not too deep my answer
Answer: 2.35 seconds rounded
Explanation:
the number unrounded us 2.352941176
Let the cannonball be thrown at a height of h above ground.
Then the potential energy of the ball is
V = m*g*h
where
m = the mass of the ball
g = 9.8 m/s²
Also, the kinetic energy of the ball is
K = (1/2)mu²
where
u = 5 m/s, the vertical launch velocity.
Ignore wind resistance.
Because the total energy is preserved, the total energy (n the form of only kinetic energy) when the ball strikes the ground is
(1/2)mV²
where V = vertical velocity when the ball strikes the ground.
Expressions for both the initial and final energy are equal regardless of whether the ball s thrown downward or upward.
Therefore there is no difference in the landing speed.
Answer: There is no difference.
Answer:
K = ½ kg m2 / s2
Explanation:
The kinetic energy rotation is given by the expression
K = ½ I w²
Where I is the moment of inertia and w is the angular velocity.
We have a relationship between linear and angular velocity
v = w r
Where r the distance from the point of rotation, in this case it is the point or where the ball is, so the linear velocity is the same as the ball.
w = v / r
We replace
K = ½ I (v / r)²
Let's calculate
K = ½ kg m2 )(m/s )/ m) 2
K = ½ kg m2 / s2
Answer:
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