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svp [43]
3 years ago
15

Write down the effect of humidity and temperature on the speed of sound.​

Physics
1 answer:
finlep [7]3 years ago
4 0

Answer:

The speed of sound is affected by temperature and humidity. Because it is less dense, sound passes through hot air faster than it passes through cold air. ... The attenuation of sound in air is affected by the relative humidity. Dry air absorbs far more acoustical energy than does moist air.

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Define the difference between the rigid body problem and a single particle problem.
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. In single particle problem whole mass is concentrated at a single point so it has a single displacement, single velocity and single acceleration. while, in rigid body mass is distributed
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Samantha is checking the weather for her upcoming trip to Mexico City. The weather forecast predicts a high-pressure system for
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Calm, sunny days with wind moving away from the center.

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a lower energy than

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Problem 3.
Korolek [52]

Answer:

143.352 watt.

Explanation:

So, in the question above we are given the following parameters or data or information that is going to assist us in answering the question above efficiently. The parameters are:

"A 1.8 m wide by 1.0 m tall by 0.65m deep home freezer is insulated with 5.0cm thick Styrofoam insulation"

The inside temperature of the freezer = -20°C.

Thickness = 5.0cm = 5.0 × 10^-2 m.

Step one: Calculate the surface area of the freezer. That can be done by using the formula below:

Area = 2[ ( Length × breadth) + (breadth × height) + (length × height) ].

Area = 2[ (1.8 × 0.65) + (0.65 × 1.0) + (1.8 × 1.0)].

Area = 7.24 m^2.

Step two: Calculate the rate of heat transfer by using the formula below;

Rate of heat transfer =[ thermal conductivity × Area (T1 - T2) ]/ thickness.

Rate of heat transfer = 0.022 × 7.24(25+20)/5.0 × 10^-2 = 143.352 watt.

8 0
3 years ago
A ball dropped from a bridge takes 3.0 seconds to reach the water below. How far is the bridge from the water?
Komok [63]
Since it is dropped, initial velocity u = 0

Using s = ut + (1/2)gt^2,        putting u = 0,  g = 10 m/s^2

s =(1/2)gt^2,                  t = 3s

s = 0.5 * 10 * 3 *3

s = 45 m.

The bridge is 45m above the water.
8 0
3 years ago
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