The frequency of the wave is 6800 Hz
<u>Explanation:</u>
Given:
Wave number, n = 20
Speed of light, v = 340 m/s
Frequency, f = ?
we know:
wave number = 

Therefore, the frequency of the wave is 6800 Hz
Answer:
Explanation:
applied Mechanics and its Growing Utilisation of Theoretical Mechanics.\
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Answer:
K.E=365.2 J
Explanation:
Given data
Weight w =953 N
radius r=1.68 m
F=73.9 N
t=2.55 s
g=9.8 m/s²
To find
Kinetic Energy K.E
Solution
From the moment of inertia

The angular acceleration is given as

The angular velocity is given as

So the Kinetic Energy is given as
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2