True . this is called a complex substance
B: Energy lose
i say this because in order to change they lose energy.
Answer: The momentum principle depends on MASS and VELOCITY.
Explanation:
The momentum principle states that net force changes the the momentum of an object where momentum is the product of the MASS of the body and it's VELOCITY.
Thus, momentum = mass(kg) ×velocity( m/s)= kgm/s ( derived unit)
Also to determine the rate of change of momentum;
Mass=m, initial velocity =u, final velocity = V and time =t
Initial momentum = mu
Final momentum = mv
Change in momentum = mv - mu
= m( v- u)
Rate of change of momentum=
m( v -u)/t --> equation 1
But V = u + at
Hence, a = v -u/t
Substitute for v -u/ t in equation 1
F = Kma, where k is constant and has the value of 1.
Therefore F = ma
Newton is the SI unit if force. It is defined as the force which gives a mass of 1kg an acceleration of 1 m/s².
IMPULSE is defined as the change of momentum of a body (mv-mu) or the product of force and time.
Thus impulse = force × time = m (v-u)
The unit is Ns ( Newton seconds) which is the same as change in momentum.
Answer:
1.84 m
Explanation:
For the small lead ball to be balanced at the tip of the vertical circle just before it is released, the reaction force , N equal the weight of the lead ball W + the centripetal force, F. This normal reaction ,N also equals the tension T in the string.
So, T = mg + mrω² = ma where m = mass of small lead ball, g = acceleration due to gravity = 9.8 m/s², r = length of rope = 1.10 m and ω = angular speed of lead ball = 3 rev/s = 3 × 2π rad/s = 6π rad/s = 18.85 rad/s and a = acceleration of normal force. So,
a = g + rω²
= 9.8 m/s² + 1.10 m × (18.85 rad/s)²
= 9.8 m/s² + 390.85 m/s²
= 400.65 m/s²
Now, using v² = u² + 2a(h₂ - h₁) where u = initial velocity of ball = rω = 1.10 m × 18.85 rad/s = 20.74 m/s, v = final velocity of ball at maximum height = 0 m/s (since the ball is stationary at maximum height), a = acceleration of small lead ball = -400.65 m/s² (negative since it is in the downward direction of the tension), h₁ = initial position of lead ball above the ground = 1.3 m and h₂ = final position of lead ball above the ground = unknown.
v² = u² + 2a(h₂ - h₁)
So, v² - u² = 2a(h₂ - h₁)
h₂ - h₁ = (v² - u²)/2a
h₂ = h₁ + (v² - u²)/2a
substituting the values of the variables into the equation, we have
h₂ = 1.3 m + ((0 m/s)² - (20.74 m/s)²)/2(-400.65 m/s²)
h₂ = 1.3 m + [-430.15 (m/s)²]/-801.3 m/s²
h₂ = 1.3 m + 0.54 m
h₂ = 1.84 m
Answer:
t = 25 seconds
Explanation:
Given that,
Distance, d = 115 m
Initial speed, u = 4.2 m/s
Final speed, v = 5 m/s
We need to find the time taken in increasing the speed.
We know that,
Acceleration, ....(1)
The third equation of kinematics is as follows :
Hence, it will take 25 seconds to increase the speed.