There are two hydrogen atoms in one molecule of water.
The answer is B) 2
Answer:
1.40 atm
Explanation:
To answer this question we can use<em> Gay-Lussac's law</em>, which states:
When volume and number of moles remain constant.
- T₁ = 23°C ⇒ 23+273.16 = 296.16 K
- T₂ = Boiling point of water = 100 °C ⇒ 100+273.16 = 373.16 K
We <u>put the known data in the equation and solve for P₂</u>:
- 1.11 atm * 373.16 K = P₂ * 296.16 K
Answer:
Explanation:
We have to start with the <u>reaction</u>:
We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:
C: 12 g/mol
O: 16 g/mol
Mg: 23.3 g/mol
If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:
In other words: 
. With this in mind, we can calculate the moles:
Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:
With the molar mass of 
(
. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:
I hope it helps!
There are 18. In each molecule of Fe(NO3)2 there are 6 oxygen atoms because you have 2 nitrate (NO3) components which each contain 3 oxygen atoms. 2 x 3 = 6. Because you have 3 molecules of Fe(NO3)2, you need to multiply 6 by 3, which gives you 18 oxygen atoms.
Answer:
6 oxygen atoms
Explanation:
From the equation,
2Fe(OH)₃ → Fe₂O₃ + 3H₂O
From the reactant (left hand side) we have 2 moles of Fe(OH)₃ having (2 * 3 = 6) atoms of oxygen and decomposed to give Fe₂O₃ which contains 3 atoms of oxygen and 3 moles of water that also contains 3 atoms of oxygen.
Since the number of oxygen participating in the reaction is independent on the product (not a reversible reaction) then the total number of oxygen atoms participating in the reaction is 6
