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larisa [96]
1 year ago
5

What is the molality of a solution prepared by dissolving 3. 41 g of c6h12o6 in 85 ml of water:__________

Chemistry
1 answer:
vovikov84 [41]1 year ago
7 0

When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.

<h3>What is molality? </h3>

Molality is the amount of a substance dissolved in a certain mass of solvent.

Molality = moles of solute/ mass of solvent (kg)

Given,

Mass of solute = 3.14g

Molar mass of solute = 180 g

Mole of solute= given mass/molar mass

= 3.14/180

= 0.0189 mol.

Volume of solvent = 85 ml

Density of water = 1 g/cm3

Density = mass/ volume

mass = density × volume

= 1× 85

= 85g

Molality = (0.0189/ 85) × 1000

= 2.2m

Thus we find that the molality of given solution is 2.2m.

learn more about molality:

brainly.com/question/26921570

#SPJ4

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A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as :_______.
Anuta_ua [19.1K]

A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as neutral.

The concentration of hydroxide ions (OH-) is measured by pOH. It is a way of expressing how alkaline a solution is. At 25 degrees Celsius, aqueous solutions with pOH values of 7 or less are neutral, whereas those with pOH values of 7 or more are acidic. The hydrogen ion potential is known as pH. The potential of hydroxide ions is known as pOH. 2. It is a scale used to estimate the hydrogen ion (H+) concentration in the solution. The hydroxide ion (OH-) concentration of the solution is measured using this scale.

pH + pOH = 14

 pOH = 3.2x 10-5

[OH-] = 10^(-pOH) =10^(- 3.2x 10-5)

= 0.99

7 0
2 years ago
Wave crests in a pond are separated by 0.2 m. The period of these waves is 0.2 s. What is the speed at which these waves travel?
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speed of wave = distance/time.
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3 years ago
Carl crumbled a piece of paper before throwing it in the trash can. Which is true about the paper after it has been crumbled
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4 0
3 years ago
How do you work out question 1a?
Sliva [168]

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

                     H₂C=CH₂   +    H₂ ⟶    H₃C-CH₃

Bonds:       4C-H + 1C=C     1H-H     6C-H + 1C-C

D/kJ·mol⁻¹:  413       612        436       413      347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

<em>For the reactant</em>s:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

<em>For the products:</em>

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

<em>For the system</em> :

ΔHrxn = 2700 - 2825 = -125 kJ

4 0
3 years ago
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