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larisa [96]
1 year ago
5

What is the molality of a solution prepared by dissolving 3. 41 g of c6h12o6 in 85 ml of water:__________

Chemistry
1 answer:
vovikov84 [41]1 year ago
7 0

When 3. 41 g of C6H12O6 is dissolved in 85 ml of water the molality is 2.2m.

<h3>What is molality? </h3>

Molality is the amount of a substance dissolved in a certain mass of solvent.

Molality = moles of solute/ mass of solvent (kg)

Given,

Mass of solute = 3.14g

Molar mass of solute = 180 g

Mole of solute= given mass/molar mass

= 3.14/180

= 0.0189 mol.

Volume of solvent = 85 ml

Density of water = 1 g/cm3

Density = mass/ volume

mass = density × volume

= 1× 85

= 85g

Molality = (0.0189/ 85) × 1000

= 2.2m

Thus we find that the molality of given solution is 2.2m.

learn more about molality:

brainly.com/question/26921570

#SPJ4

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2 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

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\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

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3 years ago
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