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yarga [219]
2 years ago
13

A potential energy diagram is shown.

Chemistry
1 answer:
Vesna [10]2 years ago
5 0

Answer:

25kJ

Explanation:

Given the initial energy to be 30kJ

The energy change from the initial energy to the peak energy = (65-30) kJ

= 35kJ

since the second energy change was a drop in energy it is regarded negative

= (55-65)

= -10kJ

Therefore total energy change

= (35-10)kJ

= 25kJ

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The hydrogen-line emission spectrum includes a line at a wavelength of 434 nm. What is the energy of this radiation? (h= 6.626 x
Andrews [41]
Wavelength = 434nm = 434 x 10⁻⁹m
planck's constant = <span>h= 6.626 x 10 ⁻³⁴ J
E =?
by using the formula;
E = hc /</span>λ
value for c is 3 x 10⁸ m/s
E = (6.626 x 10 ⁻³⁴ J)(3 x 10⁸ m/s) / 434 x 10⁻⁹m
E = 1.9878 x 10⁻²⁵ / 434 x 10⁻⁹m
E = 4.58 x 10⁻¹⁹ joules

6 0
3 years ago
Which metal atoms can form ionic bonds by losing electrons from both the outermost and next to outermost principal energy levels
RoseWind [281]

Full question options;

(Fe, Pb, Mg, or Ca)

Answer:

Iron - Fe

Explanation:

We understand tht metals pretty much form bonds by losing their valence (outermost electrons). But this question specifically asks for metals that lose beyond their outermost electrons; next to outermost principal energy levels.

Pb, Mg, and Ca only lose their outermost electrons to form the following ions;

Pb2+, Mg2+, and Ca2+.

This is because their ions have achieved a stable octet configuration - the dreamland of atoms where they are satisfied and don't need to go into reactions again.

Iron on the other hand has the following electronic configurations;

Fe:  [Ar]4s2 3d6

Fe2+:  [Ar]4s0 3d6

Fe3+:  [Ar]4s0 3d5

This means ion can lose both the ooutermost electrons (4s) and next to outermost principal energy levels (3d). So correct option is Iron.

5 0
3 years ago
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
Read 2 more answers
2. Calculate the mass of Kool-Aid needed to make 0.1 L solutions at the following concentrations: a. 0.1 M b. 0.2 M c. 0.3 M d.
murzikaleks [220]
477889654 that the mass
4 0
2 years ago
5) Some students believe that teachers are full of hot air. If I inhale 2.2 liters of gas at a temperature of 180 C and it heats
ahrayia [7]

Given :

If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs.

To Find :

The new volume of the gas.

Solution :

Since, their is no information about pressure, so we will assume that pressure is constant.

We know, relation between temperature and volume in constant pressure is :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Putting all given values in above equation, we get :

V_2 = \dfrac{V_1\times T_2}{T_1}\\\\V_2 = \dfrac{2.2\times (180+273)}{(380+273)}\\\\V_2 = 1.53 \ liters

Hence, this is the required solution.

8 0
3 years ago
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