The shortest distance taken by the object to reach the destination at a minimum time is called acceleration. Thus value acceleration depends upon the displacement and time.
Answer: The compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Explanation:
If electronegativity difference between two atoms is less than 0.4 then bond formed is a pure covalent bond.
If electronegativity difference between two atoms is between 0.4 to 1.8 then bond formed is a polar covalent bond.
If electronegativity difference between two atoms is greater than 1.8 then bond formed is an ionic bond.
The electronegativity value of a nitrogen atom is 3.04. Hence, the electronegativity difference of 
molecule is as follows.
As the electronegativity difference is 0 which is less than 0.4.
Hence, we can conclude that the compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Answer:
86.6 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 56.8 mL
Initial pressure (P₁) = 664 mmHg
Initial temperature (T₁) = 135 K
Final pressure (P₂) = 632 mmHg
Final temperature (T₂) = 196 K
Final volume (V₂) =?
The final volume of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
664 × 56.8 / 135 = 632 × V₂ / 196
Cross multiply
135 × 632 × V₂ = 664 × 56.8 × 196
85320 × V₂ = 7392179.2
Divide both side by 85320
V₂ = 7392179.2 / 85320
V₂ = 86.6 mL
Therefore, the final volume of the gas is 86.6 mL
B. sounds like the most reasonable answer.
With an increase of people studying space exploration and sharing their discoveries, then it is likely for it to inspire other people in study science as well.
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1 g
Mass of CO₂ = 3.14 g
Mass of H₂O = 1.29 g
Empirical formula =?
Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:
For Carbon, C:
Mass of CO₂ = 3.14 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Molar mass of C = 12 g/mol
Mass of C =?
Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂
Mass of C = 12/44 × 3.14
Mass of C = 0.86 g
For hydrogen, H:
Mass of C = 0.86 g
Mass of compound = 1 g
Mass of H =?
Mass of H = (Mass of compound) – (mass of C)
Mass of H = 1 – 0.86
Mass of H = 0.14 g
Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:
Mass of C = 0.86 g
Mass of H = 0.14 g
Divide by their molar mass
C = 0.86 / 12 = 0.07
H = 0.14 / 1 = 0.14
Divide by the smallest
C = 0.07 / 0.07 = 1
H = 0.14 / 0.07 = 2
Thus, the empirical formula of cyclopropane is CH₂
