Pure water is an electrolytic solution. True False

Which metal can be extracted from bauxite ore?

Finger [1]

Aluminum
Bauxite ore is the world's primary source of aluminum. The ore must first be chemically processed to produce alumina (aluminum oxide). Alumina is then smelted using an electrolysis process to produce pure aluminum metal. Bauxite is typically found in topsoil located in various tropical and subtropical regions.

8 0

3 years ago

Read 2 more answers

What is the weighted average of a nail in the sample data given?

Natalka [10]

The weighted average of the nail in accordance with the given data is 11.176g.

<h3>How to calculate weighted average?</h3>

Weighted average is an arithmetic mean of values biased according to agreed weightings.

The weighted average of the nail in the image above can be calculated by multiplying the decimal abundance with the mass of the nail, then summed up as follows;

Weighted average = (decimal abundance × mass 1) + (decimal abundance × mass 2)

Weighted average = (0.12 × 3.3) + (0.88 × 12.25)

Weighted average = 0.396 + 10.78

Weighted average = 11.176g

Therefore, 11.176g is the weighted average of the nail

Learn more about weighted average at: brainly.com/question/28042295

#SPJ1

5 0

1 year ago

2) A common "rule of thumb" -- for many reactions around room temperature is that the

babunello [35]

The question is incomplete. The complete question is :

A common "rule of thumb" for many reactions around room temperature is that the rate will double for each ten degree increase in temperature. Does the reaction you have studied seem to obey this rule? (Hint: Use your activation energy to calculate the ratio of rate constants at 300 and 310 Kelvin.)

Solutions :

If we consider the activation energy to be constant for the increase in 10 K temperature. (i.e. 300 K → 310 K), then the rate of the reaction will increase. This happens because of the change in the rate constant that leads to the change in overall rate of reaction.

Let's take :

$T_1=300 \ K$

$T_2=310 \ K$

The rate constant = $K_1 \text{ and } K_2$ respectively.

The activation energy and the Arhenius factor is same.

So by the arhenius equation,

$K_1 = Ae^{-\frac{E_a}{RT_1}}$ and $K_2 = Ae^{-\frac{E_a}{RT_2}}$

$\Rightarrow \frac{K_1}{K_2}= \frac{e^{-\frac{E_a}{RT_1}}}{e^{-\frac{E_a}{RT_2}}}$

$\Rightarrow \frac{K_1}{K_2}= e^{-\frac{E_a}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)}$

$\Rightarrow \ln \frac{K_1}{K_2}= - \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

Given, $E_a = 0.269$ J/mol

R = 8.314 J/mol/K

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{0.269}{8.314} \left(\frac{1}{300} -\frac{1}{310} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{0.269}{8.314} \times \frac{10}{300 \times 310}$

$\Rightarrow \ln \frac{K_2}{K_1}= 3.479 \times 10^{-6}$

$\Rightarrow \frac{K_2}{K_1}= e^{3.479 \times 10^{-6}}$

$\Rightarrow \frac{K_2}{K_1}= 1$

∴ $K_2=K_1$

So, no this reaction does not seem to follow the thumb rule as its activation energy is very low.

8 0

2 years ago

Question 43 please. i’m not sure if i got the right answer

hram777 [196]

a) The reaction is exothermic since the overall enthalpy change is negative. this means that the system has lost energy to the environment, namely, the apparatus and due to drought.

b) We first calculate the number of moles in 3.55 grams of magnesium.

number of moles= mass/ atomic mass

=3.55/24

=0.1479 moles(to 4sf)

now, if 2 moles of magnesium give -1204kJ

How much energy is given by 0.1479 moles

= (0.1479×-1204kJ)

=-89.0358kJ (don't forget the negative sign)

c) two molesof MgO produces -1204kJ of energy

then -234kJ will be produced by

=(-234kJ×2moles)/1204kJ

=0.3887moles

one mole of MgO weighs 24+16=40

therefore the mass produced is 0.3887moles×40=15.548grams

(d) we first find the number of moles of MgO in 40.3 grams

number of moles=mass/RFM

=40.3g/40= 1.0075moles

if 2 moles of MgO give 1204 kJ then decomposing 1.0075 moles requires

(1.0075 moles×1204kJ)/2=606.515kJ

4 0

3 years ago

elements on the right side of the periodic table differ from the elements on the left side in that elements on the right side

yarga [219]

Element on the right side of the periodic table differ from the elements on the left side in that elements on the right side are non metallic and tends to be gases at room temperature.

Explanation

In the periodic table there element in the right side , left side and those which are in between.

Example of element in the right side is fluorine chlorine, neon, Argon among others.

This element have higher effective nuclear charges and stabilize electrons more effectively.
there electrostatic intermolecular forces are generally weak therefore they exist in liquid or gaseous state.

7 0

3 years ago