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julsineya [31]
3 years ago
6

The sampling distribution of the sample mean often has approximately a normal distribution. As the sample size increases, the sa

mpling distribution of the sample mean has a more bell-shaped appearance. For relatively large sample sizes, the sampling distribution is bell shaped even if the population is highly discrete or highly skewed. This is known as the
Physics
2 answers:
finlep [7]3 years ago
5 0

Answer: The Central Limit Theorem

Explanation:

The description above explains the central limit theorem which states that given a population having mean U and standard deviation S, and drawing different large sample sizes from the population with replacement, then the distribution of the sample means will be normally distributed approximately and that this condition will be the case whether the distribution is skewed or normal.This hold if the sample size n is at least 30.

igor_vitrenko [27]3 years ago
3 0

Answer:

For this case the best answer would be the "Central Limit theorem" or CLT since we are assuming that we have a large sample size (n>30) so then all the conditions are satisfied to assume a normal distribution for the sample mean \bar X

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

For this case the best answer would be the "Central Limit theorem" or CLT since we are assuming that we have a large sample size (n>30) so then all the conditions are satisfied to assume a normal distribution for the sample mean \bar X

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3 years ago
1. What are the three ways an object can accelerate?
solong [7]

Answer:

increase speed, decrease speed, and change direction

Explanation:

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3 years ago
A beam of light from a laser illuminates a glass how long will a short pulse of light beam take to travel the length of the glas
Eduardwww [97]

Answer:

The time of short pulse of light beam is 2.37\times10^{-9}\ sec

Explanation:

Given that,

A beam of light from a laser illuminates a glass.

Suppose, the length of piece is L=25.21\times10^{-2}\ m

Index of refraction is 2.83.

We need to calculate the speed of light pulse in glass

Using formula of speed

v=\dfrac{c}{\mu}

Put the value into the formula

v=\dfrac{3\times10^{8}}{2.83}

v=1.06\times10^{8}\ m/s

We need to calculate the time of short pulse of light beam

Using formula of velocity

v=\dfrac{d}{t}

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{25.21\times10^{-2}}{1.06\times10^{8}}

t=2.37\times10^{-9}\ sec

Hence, The time of short pulse of light beam is 2.37\times10^{-9}\ sec

3 0
4 years ago
4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx
frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

Ix=.\frac{Req}{Rx} *Itotal (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2}  } (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

Req.=\frac{ 100*R1}{R1+100} (3)

Now substituting (3) in (1).

25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

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3 years ago
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Answer:

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Explanation:

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6 0
3 years ago
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