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Virty [35]
3 years ago
7

What is the concentration of magnesium bromide, in ppm, if 133.4 g MgBr2 dissolved in 1.84 L water. Then solve for the bromine c

oncentration in ppm
Chemistry
1 answer:
Serhud [2]3 years ago
7 0

Answer: 0.0725ppm

Explanation:

133.4g of MgBr2 dissolves in 1.84L of water.

Therefore Xg of MgBr2 will dissolve in 1L of water. i.e

Xg of MgBr2 = 133.4/1.84 = 72.5g

The concentration of MgBr2 is 72.5g/L = 0.0725mg/L

Recall,

1mg/L = 1ppm

Therefore, 0.0725mg/L = 0.0725ppm

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