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krok68 [10]
3 years ago
10

Which number is irrational, an integer, and a real number?

Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

name me some numbers plz

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Check if 7 is a solution of the equation 4 ( Z - 3 ) = 16. step by step plz guys. ​
Vilka [71]

Answer:

YES

Step-by-step explanation:

4(Z-3)=16

4Z-12=16

  +12 +12

4Z=28

Z=7

3 0
2 years ago
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Helppp!!!! please!!!
KatRina [158]

Answer:

Option B is the correct answer

Step-by-step explanation:

Center of the circle lie on point (-1, - 3) = (h, k)

\implies \: h =  - 1 \:  \: k =  - 3 \\radius \: r \:  = 2  \\ equation \: of \: circle \: in \: standard \: form \:  \\ is \: given \: as :  \\  {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}  \\  {(x  +  1)}^{2}  +  {(y  +  3)}^{2}  =  {2}^{2}  \\  \purple{ \boxed{ \bold{ {(x  +  1)}^{2}  +  {(y  + 3)}^{2}  = 4}}}

8 0
2 years ago
a bag is filled with blue and green marbles. there are three rimes as many blues as green ones. if the bag contains 280 marbles
Anna11 [10]
There are 210 blue marbles! 
6 0
3 years ago
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Jon and Becky measured the circle shaped part of a sun they drew on the sidewalk. The diameter of the circle is 53 centimeters.
UNO [17]
Hello!

To find the area, we use the formula A=pir², where pi=3.14 and r= the radius.

To solve, we find half of the diameter, which is the radius. Half of 53 is 26.5. We square this number and then multiply it by pi. 26.5·26.5=702.25. Now we multiply by pi. 702.25·3.14=2,205.065.

Our final answer is about 2,205.1 cm².

I hope this helps!
3 0
3 years ago
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Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. ex = 3 − 2x, (0
raketka [301]

Answer:

f(0)=-2\\f(1)=e-1

Step-by-step explanation:

According to intermediate value theorem, if a function is continuous on an interval [a,b], and if k is any number between f(a) and f(b), then there exists a  value, x=m, where a, such that f(m)=k

In the given question,

Intermediate Value Theorem is used to show that there is a root of the given equation in the specified interval.

Here,

f(x)=e^x-3+2x

Put x=0

f(0)=e^0-3+2(0)=1-3+0=-2

Put x=1

f(1)=e^1-3+2(1)=e-3+2=e-1

3 0
2 years ago
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