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Evgen [1.6K]
3 years ago
14

Galileo had some unique personality traits. He was highly curious and observant, had the courage to challenge authorities and pr

econceived notions, and always held truth over everything else. Give evidence from his life to support this statement.
Physics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

Galileo is one of the most revolutionary scientists in terms of the novelty of his ideas.

He made great advances in the laws of motion and astronomical matters, as well as the creation of telescopes, making the first observations of the Moon, Venus and Jupiter satellites.

He supported Copernicus's idea that the earth revolves around the sun, which was a controversial idea for his time, and the reason why his books were banned because the idea that the earth was not the center of the universe was not yet a well received idea.

For his ideas he was persecuted by the Inquisition and accused of heresy, but he was a proud man and stayed true to his ideas .

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A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track. If the car started from rest at the t
yawa3891 [41]
The only thing acting as the roller coaster gets to the bottom is gravity thus
acceleration is 9.81

so u use the formula
vf^2 = vi^2 + 2abetaD
thus
distance = vf^2 - vi^2 divided by 2a
so 26^2 - 0^2 divided by 2(9.81m/s)
equals 676 divided by 2(9.81m/s)
= 34.45463812m
then use the appropriate 3 sig digs
so 34.5m
hopes this helps 
6 0
4 years ago
Which option is an example of a physical property?
Aleksandr-060686 [28]

state of matter is tha ans

3 0
3 years ago
I need help someone please
Rzqust [24]

Answer:

we neglect the 190N to answer that Question

8 0
3 years ago
If the mass of an object is 176 and Net force is 50, what would be the Acceleration?
pochemuha

Answer:

0.28m/s²

Explanation:

Force = mass•acceleration

F = m•a

50 = 176•a Divide both sides by 176:

50/176 = a ≈ 0.28 m/s²

6 0
3 years ago
Assuming the earth is a uniform sphere of mass M and radius R, show that the acceleration of fall at the earth's surface is give
Keith_Richards [23]

Explanation:

The weight of an object on the surface of the earth is equal to the gravitational force exerted by the earth on the object.

W=F_G

mg = G \dfrac{mM}{R^2}

which gives us an expression for the acceleration due to gravity <em>g</em> as

g = G\dfrac{M}{R^2}

At a height h = R, the radius of a satellite's orbit is 2R. Then the acceleration due to gravity g_h at this height is

mg_h = G \dfrac{mM}{(2R)^2}= G \dfrac{mM}{4R^2}

Simplifying this, we get

g_h= G \dfrac{M}{4R^2} = \dfrac{1}{4} \left(G \dfrac{M}{R^2} \right) = \dfrac{1}{4}g

3 0
3 years ago
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